What is 575 written as a mixed number

Mathematics

1 answer:

bonufazy [111]3 years ago

4 0

Answer:

5 3/4

Step-by-step explanation:

575/100==23/4=5 3/4

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The degree measure of an acute angle in a right triangle is x. If sinx=2/3, determine if each of the following expressions is al

leonid [27]

<h2> ☞ANSWER☜ </h2>

The right triangle has one 90 degree angle and two acute (< 90 degree) angles. Since the sum of the angles of a triangle is always 180 degrees... The two sides of the triangle that are by the right angle are called the legs... and the side opposite of the right angle is called the hypotenuse.

An acute angle is an angle that measures less than 90 degrees. A triangle formed by all angles measuring less than 90˚ is also known as an acute triangle. For example, in an equilateral triangle, all three angles measure 60˚, making it an acute triangle.

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Alexeev081 [22]

2x(-5x-3)

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3 years ago

What is the surface area of the triangular prism shown?

Lunna [17]

Answer:

The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 15\ cm$

$Area = 375\ cm^2$

The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 12\ cm$

$Area = 300\ cm^2$

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 9\ cm$

$Area = 225\ cm^2$

The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

$Area = \frac{1}{2}* b*h$