An inequality that describes the widths (w) that will yield a fenced-in area of at least 50 square feet is
.
- Let the length of the rectangle be L.
- Let the width of the rectangle be W.
<u>Given the following data:</u>
- Length of rectangle = 10 feet.
- Area of rectangle ≥ 50 square feet.
To write an inequality that describes the widths (w) that will yield a fenced-in area of at least 50 square feet:
<h3>How to calculate the area of a rectangle.</h3>
Mathematically, the area of a rectangle is given by the formula;
![A=LW](https://tex.z-dn.net/?f=A%3DLW)
<u>Where:</u>
- A is the area of a rectangle.
- L is the length of a rectangle.
- W is the width of a rectangle.
Substituting the given parameters into the formula, we have;
![50\geq 10W\\\\W\geq \frac{50}{10} \\\\W\geq 5](https://tex.z-dn.net/?f=50%5Cgeq%2010W%5C%5C%5C%5CW%5Cgeq%20%5Cfrac%7B50%7D%7B10%7D%20%5C%5C%5C%5CW%5Cgeq%205)
<u>Note:</u> The width would start from 5 on the number line with the arrow pointing rightward.
Read more on area of a rectangle here: brainly.com/question/25292087
Answer:
![\dfrac{1}{j^8}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7Bj%5E8%7D%20)
Step-by-step explanation:
![(j^2)^{-4} = j^{2 \times (-4)} = j^{-8} = \dfrac{1}{j^8}](https://tex.z-dn.net/?f=%28j%5E2%29%5E%7B-4%7D%20%3D%20j%5E%7B2%20%5Ctimes%20%28-4%29%7D%20%3D%20j%5E%7B-8%7D%20%3D%20%5Cdfrac%7B1%7D%7Bj%5E8%7D)
Answer: 8 weeks
explanation: 125 + 15x = 245
You then have to subtract 125 from both sides so we can isolate our variable which will give us 15x = 120 . Divide 15 from both sides : 15x/15 = 120/15 which will give us x = 8.
Answer:
I think 3
Step-by-step explanation:
I'm not totally for sure about it though. sorry :(