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Oduvanchick [21]
3 years ago
9

Two numbers are respectively twenty percent and ten percent more than the third number. How many percent is the first number mor

e than the second ?​
Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

10%

Step-by-step explanation:

Let the third number is X.

then first number = (100-30)% of X

= 70% of X = 7X/10

Second number is (63X/100)

Difference = 7X/10 - 63X/100 = 7X/10

So required percentage is, difference is what percent of first number

=> (7X/100 * 10/7X * 100 )% = 10%

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16x2 + 10x – 27 = -6x + 5<br> What are the solutions to this equation ?<br> X<br> x=
bonufazy [111]

Answer:

x=-2              x=1

Step-by-step explanation:

16x2 + 10x – 27 = -6x + 5

Add 6x to each side

16x^2+6x + 10x – 27 = -6x+6x + 5

16x^2 +16x -27 = 5

Subtract 5 from each side

16x^2 + 16x – 27-5 = 5 - 5

16x^2 +16x -32 = 0

Factor out 16

16 (x^2 +x-2)=0

Factor

16 (x+2) (x-1) =0

Using the zero product property

  (x+2) =0     x-1=0

x=-2              x=1

5 0
3 years ago
Aunty Joan packs a packet of sweets to Alice and Olivia. Alice and Olivia share sweets in the ratio 7:3. Alice gives 3 sweets to
aivan3 [116]

Initially, Alice had 28 sweets and Olivia 12 sweets.

Step-by-step explanation:

First assume that Aunty Joan has x number sweets.

Alice and Olivia shared the x sweets in a ration of 7:3, this means

Alice had 7/10 x sweets and Olivia had 3/10 sweets.

Alice gives 3 sweets to Olivia, Alice will remain with ;

\frac{7}{10} x-3

Then the new ratio changes to 5:3 which means Alice will have 5/8 x number of sweets.

Equate the number of sweets for Alice in the two cases, which is

\frac{5}{8}x=\frac{7}{10} x-3\\ \\\frac{7}{10} x-\frac{5}{8} x=3\\

\frac{56x-50x}{80} =3\\\\\\\frac{6}{80} x=3\\\\\\6x=80*3\\\\\\x=240/6\\\\x=40

So there were 40 sweets at first

Using the ratio of 7:3 then

Alice had 7/10 *40 = 28 sweets

Olivia had 3/10*40= 12 sweets

Alice gave Olivia 3 sweets, so she will remain with 28-3 =25 sweets. Olivia will now have 15 sweets.The new ratio will be 25:15 simplified as 5:3.

Learn More

Ratio : brainly.com/question/11095585

Keywords : Ratio

#LearnwithBrainly

5 0
3 years ago
Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
_____ have congruent corresponding parts.
aniked [119]

Answer:

Two congruent figures

Step-by-step explanation:

Here we have to use the definition of congruent.

Congruent means equal to each other.

Example.

If the two triangles said be congruent, their corresponding angles and corresponding sides are equal.

They will have to same size of the sides and same measure of angles.

Two equal polygons, that is two congruent figures.

Hope this will help you.

Thank you.

4 0
3 years ago
At a party there are 40 cookies. There are 5 chocolate cookies for every 3 oatmeal cookies,how many oatmeal cookies are there
Pavel [41]
The answer is: 15

Because if for every 5 c cookies there is 3 oatmeal cookies, we can add 5+3=8. 40 divided by 8= 5. 5 times 3 equals 15. That’s why the answer is 15

4 0
3 years ago
Read 2 more answers
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