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Pani-rosa [81]
3 years ago
9

Solve each equation by graphing the related function. If th equation has no real number solution, write no solution. X^2 + 7 = 0

Mathematics
2 answers:
Brrunno [24]3 years ago
6 0
Answer:
The equation x² + 7 = 0 has no solution

Explanation:
1- using graph:
To solve the equation means graphically means to find the x-intercepts.
The attached image shows the graph of the given function.
We can note that there are no x-intercepts. This means that the given function has no real solutions

2- using algebra:
To solve the equation algebraically means to find the values of x that would make the equation equal to zero.
Solving the given equation, we would find that:
x² + 7 = 0
x² = -7
x = <span>± </span>√-7
The square root of a negative number will always give imaginary values. This means that the equation has no real solutions

Hope this helps :)

CaHeK987 [17]3 years ago
4 0
The answer is D. It has no solution
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Please solve this problem because tomorrow is my exam.<br><br>​
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Step-by-step explanation:

a). A = {x  ∈ R  I  5x-8 < 7}

5x - 8 < 7 <=> 5x < 8+7  <=> 5x < 15  =>

x < 3  => A = (-∞ ; 3)

A ∩ N = {0 ; 1 ; 2}

A - N* = (-∞ ; 3) - {1 ; 2}

b).  A = { x ∈ R  I  7x+2 ≤ 9}

7x+2 ≤ 9 <=> 7x ≤ 7  => x ≤ 1 => x ∈ (-∞ ; 1]

A ∩ N = {0 ; 1}

A-N* = (-∞ ; 1)

c). A = { x ∈ R  I  I 2x-1 I < 5}

I 2x-1 I < 5  <=> -5 ≤ 2x-1 ≤ 5  <=>

-4 ≤ 2x ≤ 6  <=> -2 ≤ x ≤ 3  => x ∈ [-2 ; 3]

A ∩ N = {0 ; 1 ; 2 ; 3}

A - N* = [-2 ; 3) - {1 ; 2}

d). A = {x ∈ R I I 6-3x I ≤ 9}

I 6-3x I ≤ 9  <=> -9 ≤ 6-3x ≤ 9  <=>

-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3  =>

-3 ≤ x ≤ 5  => x ∈ [-3 ; 5]

A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}

A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}

4 0
2 years ago
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Hitman42 [59]

Answer: n minus c would equal c c minus b would equal z

Step-by-step explanation:

3 0
3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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