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WARRIOR [948]
4 years ago
9

2. A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius r. A passenger feels the seat

of the car pushing upward on her with a force equal to five times her weight as she goes through the dip. Of r = 21.5 m, how fast is the roller coaster traveling at the bottom of the dip?
Physics
1 answer:
vekshin14 years ago
6 0

Answer:v=\sqrt{4gr}

Explanation:

Given

Passenger feels the seat of the car Pushing upward with a force equal to five times her weight

Therefore

N-mg=\frac{mv^2}{r}

it is given N=5mg

where N=normal reaction

5mg-mg=\frac{mv^2}{r}

thus v=\sqrt{4gr}

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ladessa [460]
Pressure is defined as the force per unit area on a body.
8 0
3 years ago
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When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Stella [2.4K]

Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 = +8.4\mu C

q_2 = +5.6 \mu C

force between two charges is given as

F = 0.66 N

now we have

F = \frac{kq_1q_2}{r^2}

0.66 = \frac{(9\times 10^9)(8.4 \mu C)(5.6 \mu C)}{r^2}

r = 0.8 m

so it is separated by 80 cm distance

3 0
3 years ago
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Below you are given data about a wave in three different substances.
aliya0001 [1]

1) The period of the wave is the same in all media

2) The speed of the wave is different depending on the medium

3) The speed, the direction and the wavelength of the wave changes, while the frequency remains the same

Explanation:

1)

The period of a wave is the time it takes for the wave to do one complete oscillation.

The period of a wave is the reciprocal of the frequency of the wave:

T=\frac{1}{f}

where

T is the period

f is the frequency

From the table given, we notice that the wave has always the same frequency in all the three media: since the period depends only on the frequency, this means that the period of the wave in the three media is the same. We can also calculate it, since we know that

f = 350 Hz

so the period is

T=\frac{1}{350}=2.86\cdot 10^{-3} s = 2.86 ms

2)

The speed of a wave is given by the wave equation:

v=f \lambda

where

f is the frequency

\lambda is the wavelength

In the first medium,

f=350 Hz, \lambda = 0.75 m, so the speed is

v_1 = (350)(0.75)=262.5 m/s

In the second medium,

f=350 Hz, \lambda = 0.70 m, so the speed is

v_2 = (350)(0.70)=245 m/s

In the third medium,

f=350 Hz, \lambda = 0.65 m, so the speed is

v_3 = (350)(0.65)=227.5 m/s

Therefore, we see that the speed of the wave is different due to the medium.

3)

When a wave travels from a medium into another, the following things happen:

- The direction of the wave changes. In particular, the wave bends towards the normal to the interface between the two media if the second medium has a greater optical density, while it bends away from the normal if the second medium has a lower optical density

- The speed of the wave changes. In particular, the wave slows down if the second medium has a greater optical density, while it speeds up if the second medium has a lower optical density

- The frequency of the wave does not change

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Learn more about waves here:

brainly.com/question/5354733

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7 0
4 years ago
Upward pull of 850 N on a 81.6 kg bale of hay. What is the magnitude of the bales acceleration?
Helen [10]

Weight = (mass) x (acceleration of gravity).

When I calculate the weight of the 81.6 kg, the number I use for gravity
is 9.807 m/s².  That gives a weight of 800.25 N, so I think that's where the
question got the crazy number of 81.6 kg ... whoever wrote the problem
wants the hay to weigh 800 N, and that's what I'll use for the weight.

The forces on the bale of hay are gravity: 800N downward, and the
guy on the truck with the pitchfork pulling upward on it with 850 N. 
The net force on the bale is (850 - 800) = 50 N upward.

Use Newton's second law of motion:  (Net force) = (mass) x (acceleration)

Divide each side by 'mass' :     
      
                        Acceleration = (net force)/(mass)

On the hay wagon,             

                        Acceleration = (50 N upward) / (81.6 kg) = <em>0.613 m/s² upward</em> 

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4 years ago
Bob is experimenting with a spring in the lab. He suspends a weight from the end of the spring, then measures the stretch of the
KATRIN_1 [288]

Answer:

answer in the picture provided.

Explanation:

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