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2 years ago

13

Write the equation of the line that passes through (-1, -3) and is parallel to the line that passes through (10, 3) and (7, -1).

1 answer:

REY [17]2 years ago

8 0

Answer:

y=4/3 x -5/3

Step-by-step explanation:

Please see attached picture for full solution.

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F(x)=11x -x +2 find the potential rational zeros

d1i1m1o1n [39]

X = - 1/2

In other way is x = -0.2 , x = -5^-1

3 0

2 years ago

Simplify the following leave the answer in radical notation:

Nataliya [291]

Answer:

1- 5xy³√5y

2- 2xy²∛3y²

Step-by-step explanation:

√125x²y^7=

√25*5x²y^6y

5xy³√5y

2) ∛24x³y^8=

∛2³*3x³y^8=

2xy²∛3y²

7 0

2 years ago

When a third of a number is subtracted from a half of the same number, 60 is the result. Find the number

AURORKA [14]

the answer is 360 because if you take a third you will have 120 then if you take half of that then you get 60

6 0

2 years ago

What are the approximate values of the non-integral roots of the polynomial equation?

irga5000 [103]

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

$f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0$

By zero product property,

$x^2+6x+8=0\ \text{or}\ x^2+6x+13=0$

Solve each equation:

1. $x^2+6x+8=0$

$D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2$

2. $x^2+6x+13=0$

$D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i$

5 0

2 years ago

Read 2 more answers

AleksAgata [21]

I think the answer is 35 km per hour because they are travelling in steady rate and the graph chart is showing the times and all

5 0

1 year ago