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Maksim231197 [3]
3 years ago
15

How many acute/obtuse/right angles does a pentagon have

Mathematics
2 answers:
Naily [24]3 years ago
4 0
It has 5 obtuse angles.
krok68 [10]3 years ago
3 0
It has no acute angles, 5 obtuse angles, and no right angles.
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Answer:

Part A:  12 plus x, the x being how much money he made on Sunday.

Part B: 2 plus x times 2

Step-by-step explanation:

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Find LeShawn's average speed in meters per hour. 1,448 meters per minute
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If he's average speed per minute is 1,448 meters per minute, and there are 60 minutes in a single hour. You would multiply 1,448 by 60 to get the answer of 86,880 meters per hour.
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Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

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  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

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3 years ago
Solve 3x to the <br> second power <br> -2x-8=0 using an algebraic method
MatroZZZ [7]

Answer:

x=2\textrm{ or } x=-\frac{4}{3}

Step-by-step explanation:

Given:

The equation is given as:

3x^{2}-2x-8=0\\3x^{2}-6x+4x-8=0\\3x(x-2)+4(x-2)=0\\(x-2)(3x+4)=0\\\\x-2=0\textrm{ or }3x+4=0\\x-2+2=0+2 \textrm{ or }3x+4-4=0-4\\x=2\textrm{ or }3x=-4\\x=2\textrm{ or}\\x=-\frac{4}{3}

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X-13y is the answer to that equation
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