Question

Solve 3x to the second power -2x-8=0 using an algebraic method

Answer 1

Answer:

$x=2\textrm{ or } x=-\frac{4}{3}$

Step-by-step explanation:

Given:

The equation is given as:

$3x^{2}-2x-8=0\\3x^{2}-6x+4x-8=0\\3x(x-2)+4(x-2)=0\\(x-2)(3x+4)=0\\\\x-2=0\textrm{ or }3x+4=0\\x-2+2=0+2 \textrm{ or }3x+4-4=0-4\\x=2\textrm{ or }3x=-4\\x=2\textrm{ or}\\x=-\frac{4}{3}$

Therefore, the possible values of $x$ are 2 and $-\frac{4}{3}$