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MAVERICK [17]
3 years ago
10

Solving Equations and Systems of Equations

Mathematics
2 answers:
otez555 [7]3 years ago
7 0

Answer:

Because they are equal

Step-by-step explanation:

Anettt [7]3 years ago
3 0
Guy above me is in fact completely correct. I suggest taking his answer.
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You earn a 90% on his science test you answer 18 questions correctly how many questions were on the test
Bogdan [553]
Hello there!

The correct answer is 20.

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8 0
2 years ago
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What is the scale factor from triangle PRQ to triangle SUT
Alex

Answer:

Scale factor is 1.5

Step-by-step explanation:

ST = PR

10/15

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8 0
3 years ago
Solve the equation : 2x + 7 = 21 and find the value of x. Is 2x + 7 = 21 a first degree equation or not?
Paraphin [41]

Answer:

The proposed equation is solved as follows:

2X + 7 = 21

2X = 21 - 7

2X = 14

X = 14 / 2

X = 7

The value of X is 7.

A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.

4 0
2 years ago
The interquartile range of a data set is 10 units. What does this represent?
babunello [35]
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4 0
3 years ago
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Help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am
zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

{\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ <em><u>a = 1 , b = - 10 , c = 2</u></em><em><u>7</u></em>

Now , Calculating D ;

{:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}

{:\implies \quad \sf D=100-108}

{:\implies \quad \bf \therefore \quad D=-8}

Now , Calculating the vertex ;

{:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}

{:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}

{:\implies \quad \bf \therefore \quad Vertex = (5,2)}

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

5 0
2 years ago
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