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svlad2 [7]
2 years ago
6

The graph shows the printing rate of Printer A. Printer B can print at a rate of 25 pages per minute. Complete this sentence: Th

e rate for Printer B is (a) ____________ the rate for Printer A because the rate of 25 pages per minute is (b) _____________ the rate of (c) __________ pages per minute for Printer A.

Mathematics
2 answers:
frez [133]2 years ago
6 0

Answer:

a equal to c 25 b greater than

Step-by-step explanation:

bulgar [2K]2 years ago
3 0

Answer:

As per graph the rate of Printer A is 15 pages per minute.

<u>Missing words are:</u>

  • (a) greater than
  • (b) greater than
  • (c) 15

The rate for Printer B is <u>greater than</u> the rate for Printer A because the rate of 25 pages per minute is <u>greater than</u> the rate of <u>15</u> pages per minute for Printer A.

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Vol=1348.79cm³. What's X? (Height)
ale4655 [162]
V = PI x r^2 x H

1348.79 = 3.14 x 5.5^2 x H

1348.79 = 94.985 x h
h = 1348.79 / 94.985
h = 14.2 cm  ( round answer if needed)


4 0
3 years ago
A number is equal to three times the smaller number also the sum of the smaller number and four is the larger number situation i
emmainna [20.7K]

Answer:

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8 0
2 years ago
A population of 200 animals has a growth rate of 1.03% each year. at this growth rate, the function f(x)=200(1.03)^x gives the p
Y_Kistochka [10]
For this case, the first thing we should do is use the following equation:
 f (x) = 200 (1.03) ^ x
 We substitute f (x) = 300:
 300 = 200 (1.03) ^ x
 We clear the value of x:
 log1.03 (300/200) = log1.03 ((1.03) ^ x)
 x = log1.03 (300/200)
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 Answer: 
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6 0
2 years ago
The graph shows y = cot(x). Which of the following are true of its inverse? Check all that apply.
uranmaximum [27]

Answer:

Zeroes: None

Domain: All real numbers

Maximum: None

Step-by-step explanation:

EDGE PRECAL 2020

5 0
2 years ago
Read 2 more answers
Y/2 - 1/5 = 2 - y/3 <br><br>please tell me this asap ​
IRISSAK [1]

Answer:

y=2 16/25

in other words, two and sixteen twenty-fifths

Step-by-step explanation:

y/2-1/5=2-y/3

Move the variables to one side and constants to the other

y/2+y/3=2+1/5

Multiply y/2 by 3/3 and y/3 by 2/2 so that they have a common denominator

3y/6+2y/6=2 1/5

5y/6=11/5

Cross multiply

66=25y

y=66/25

y=2 16/25

HOPE THIS HELPS!!!

4 0
3 years ago
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