All categories

2 years ago

3c-d=T Could you solve for c

2 answers:

7 0

- - Let's solve for C.

Starting off with our equation:
$3c+d=T$

Transform:
$3c=T+D$

Solve for that:
$\frac{3c}{3} = \frac{T+D}{3}$

Solve for that for the last time and your answer is $\frac{T+D}{3} =C$

Nady [450]2 years ago

3 0

Yes, we can solve for c.

3c - d=T
+d +d

3c = t+d

3c/3 = $\frac{t+d}{3}$

Answer: $c = \frac{t + d}{3}$

You might be interested in

How to use substitution to solve system of equations

svlad2 [7]

Answer: See explanation.

Step-by-step explanation:

Let's assume that you have a System of two equations. You can solve this System using the Substitution Method.

In order to use that method to solve the System of equations, you can follow the steps shown below:

Step 1: You must choose one of the equations of the system and solve for one of the variables. Let's call this new equation "Equation A"

Step 2: Then you must substitute"Equation A" into the other equation.

Step 3: Now you must solve for the other variable in order to find its value.

Step 4: Finally, you need to substitute the value of the variable obtained in the previous step, into the "Equation A" and then evaluate in order to find the value of the other varibale.

(Note: You can also substitute the value of the variable calculated in Step 3 into any original equation and solve for the other variable to find its value).

4 0

2 years ago

A sales associate at a computer electronics store

mote1985 [20]

Answer:

the sales associate has to sell 4 computers to make the same amount of money under both plans

Step-by-step explanation:

y=money

x=computers sold

Plan 1: y=30x+180

Plan 2: y=75x

75x=30x+180

45x=180

x=4

7 0

2 years ago

A jar contains 38 red marbles numbered 1 to 38 and 38 blue marbles numbered 1 to 38 a marble is drawn at random from the jar

liq [111]

Answer:

$P(Red) = 0.50$ '

$P(Odd) = 0.50\\$

Step-by-step explanation:

Given

$Red = 38$

$Blue = 38$

Required (Missing part of the question)

(a) The marble is red. (b) The marble is odd-numbered

Solving (a): Probability of Red.

This is calculated as:

$P(Red) = \frac{Red}{Total}$

$P(Red) = \frac{38}{38+38}$

$P(Red) = \frac{38}{76}$

$P(Red) = 0.50$

Solving (b): Probability of Odd

Since each marble type is numbered 1 to 38, then half of it are odd.

i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.

So, the probability of odd is:

$P(Odd) = \frac{Odd}{Total}$

$P(Odd) = \frac{19+19}{38+38}$

$P(Odd) = \frac{38}{76}$

$P(Odd) = 0.50\\$

5 0

3 years ago

Round 28520 to the nearest tenths

Alex17521 [72]

Answer:

asdfghyjukmng

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Given that measure OAB equals 45. What is the area of the shaded portion of the circle?

Nat2105 [25]

Answer:

D. $8\pi-16$

Step-by-step explanation:

A circle measures 360 degrees and has an area $A=\pi{r}^2$

The radius (also side length) is given: $4\sqrt{2}$ .

The area of this circle is $A=\pi\cdot{4}{\sqrt{2}}^2=32\pi$

The area of a triangle is (1/2)bh, so this triangle is: $(\frac{1}{2})\cdot 4\sqrt{2}\cdot4\sqrt{2}=A$

Triangle area: A = 16 units^2.

This is a right triangle that's also a 45, 45, 90 triangle. In these special triangles, the side lengths (AO and OB) will be the same. It also means the hypotenuse is such side length times the sqrt of 2.

Now, subtract the area of the triangle from 1/4 of the circle's area:

(1/4)32pi - 16 = 8pi - 16

8 0

2 years ago