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Rainbow [258]
3 years ago
13

EASY MATH HELP

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
The percent error in Marcela's estimate is 612÷735=8.3%.

The actual speed of the car is either 57 mph or 63 mph. (60×0.05=3, 60-3=57 mph or 60+3= 63 mph)
Basile [38]3 years ago
7 0

Answer:

The answer is 57 mph or 63mph

Step-by-step explanation:

i did the test

You might be interested in
Can someone help me understand this and show work
ELEN [110]

So first off, the most important thing in Geometry is to know the relationship between angles and lines. A vertical line is 180 degrees, a line bisecting something means that whatever is bisected is equal to the other side, vertical angles are equal to each other, etc. Once you understand these it will be a breeze. Make sure you always write down the numbers you find out on the problem in its place so you can keep on track and visualize it better!

8) The 2 angles represented by the equations are being bisected by a vertical line. So that means they are equal to each other and we can solve by putting that into an equation. 5x-46=2x+5, 3x-46=5, 3x=51, x=17. Now just plug in 17 for x. 5(17)-46, 85-46=39. <PQR=39

9) A linear pair is just 2 angles that make a 180 degree angle so, 1, 4, & 5

10) A vertical angle is an angle that is equal and opposite to the other. In this case the only clear one is 1 & 4 (Answer) but angles 2 and 3, when added, would equal angle 5.

11) Supplementary means it equals 180 degrees so the same as #9. 1 & 5, 4 & 5

12) Set 3x+20 and y-20 have different variables, it is easier to use x and 3x+20.Both of these angles form a linear pair, which means they equal 180 so set both of them equal to it. 3x+20+x=180. Combine like terms. 4x+20=180, 4x=160, x=40. Now plug in 40 for x. Since one angle is just x and x=40, subtract that from 180 to find the other angle. We now know y-20=140 so we can simply work out the equation. y-20=140, y=160. Our final answer is x=40 and y=160.

13) (sorry its too blurry I can't risk it but i'm sure you get it now) Just set the angles equal to each other to find the first angle and subtract the angle from 180 to get the other angle.

14) Line AOC equals 180 so that means if <AOB =90 then <BOC equals 90. Line BOE is also a supplementary angle meaning if we add up all the numbers we now know on the line (90,75) they would equal 165. 180-165= 15 meaning <COD=15 degrees. Since <COD is 15 and <DOE is 75 we can add those up and subtract it from 180 (then add 75 again) to find <AOD. 75+15=90 (right angles are 90). 90+75=165, so <AOD=165 degrees.

I hope I didn't get anything wrong I was in a bit of a rush. Just remember the rules and the relationships and you'll do great!


7 0
3 years ago
I need the quadratic formula.
Gre4nikov [31]
ax²+bx+c=0
4a²x²+4abx+4ac=0
4a²x²+4abx=-4ac
4a²x²+4abx+b²=b²-4ac
(2ax+b)²=b²-4ac
3 0
3 years ago
[Pre-Calc] Please Help! I don’t know where to start. How do I do this?
sertanlavr [38]

Answer:

See Below.

Step-by-step explanation:

Problem A)

We have:

\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta

When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.

So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:

\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta

Cancel:

\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta

Let 1/cosθ = secθ:

\sec^2\theta -1=\tan^2\theta

From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:

\tan^2\theta =\tan^2\theta

Problem B)

We have:

\sin^3x=\sin x-\sin x \cos^2 x

Factor out a sine:

\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x

From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:

\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x

Distribute:

\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x

Problem C)

We have:

\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x

Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:

\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x

From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:

\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x

Cancel:

\displaystyle \frac{\cos x}{\sin x}=\cot x

By definition:

\cot x = \cot x

3 0
3 years ago
Help me please with this
Reptile [31]
The shape has no right angles
4 0
3 years ago
Read 2 more answers
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.3 in​, and a standard deviation given by
Salsk061 [2.6K]

Answer: a)  0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean : \mu= 62.3\text{ in}

Standard deviation : \sigma = \text{2.4 in}

The formula for z -score :

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

a) Sample size = 1

For x= 63 in. ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29

The p-value = P(z

0.6140918\approx0.6141

Thus, the probability is approximately = 0.6141

b)  Sample size = 47

For x= 63 ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0

The p-value = P(z

=0.9772498\approx0.9772

Thus , the probability that they have a mean height less than 63 in =0.9772.

8 0
4 years ago
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