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Rainbow [258]
4 years ago
13

EASY MATH HELP

Mathematics
2 answers:
Amiraneli [1.4K]4 years ago
8 0
The percent error in Marcela's estimate is 612÷735=8.3%.

The actual speed of the car is either 57 mph or 63 mph. (60×0.05=3, 60-3=57 mph or 60+3= 63 mph)
Basile [38]4 years ago
7 0

Answer:

The answer is 57 mph or 63mph

Step-by-step explanation:

i did the test

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Match each three dimensional figure to its volume based on the given dimensions.
Gre4nikov [31]

please attach a diagram

6 0
3 years ago
Helppppppp!!!! Pleaseeee
Sergeeva-Olga [200]

Answer:

2.9×

{10}^{8}

5 0
2 years ago
The sum of three consecutive odd numbers is 69. What are the three numbers?
n200080 [17]

Answer:

21, 23, 25

Step-by-step explanation:

Ok, so this one may seem a little tricky, so I'll try to explain it as best as I can. :)

So because they are consecutive odd numbers, that means they are odd numbers that are one after the other. This means each number is 2 apart from the next. So by using this, we know that there is a difference of 6 between the highest and lowest number. Now let's try and make an equation:

3o + 6 = 69

Now in order to get O by itself we have to subtract 6 from both sides:

3o = 63

Now we just have to divide by three on both sides:

o = 21

So now, we know that the lowest number is 21, but we have to add 2 to get 23, and then another 2 to get 25.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
A student rounds a number to 12.9. Which of the following is a possible value of the original number?
LekaFEV [45]

Answer:

12.85, 12.86, 12.87, 12.88, 12.89, 12.90, 12.91, 12.92, 12.93, and 12.94

Step-by-step explanation:

there is none

3 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
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