Answer:
So it would takes approximately 6.9 hours to reach 32 F.
Step-by-step explanation:
For this case we have the following differential equationÑ
We can reorder the expression like this:
We can use the substitution 
and 
so then we have:
IF we integrate both sides we got:
If we apply exponential in both sides we got:
And if we replace w = u-T we got:
We can also express the solution in the following terms:
For this case we know that 
since w ehave a cooloing, 
, we have this model:
And if we want that the temperature would be 32F we can solve for t like this:
If we apply natural logs on both sides we got:
So it would takes approximately 6.9 hours to reach 32 F.
We know that m<JKL = m<JKM + m<MKL
Let's substitute the values from the picture into our equation above.
10x - 11 = 43 + 8x - 20
Combine like terms.
10x - 11 = 8x + 23
Subtract 8x from both sides and add 11 to both sides.
2x = 34
Divide both sides by 2
x = 17
m<MKL = 8x - 20 = 8(17) - 20 = 136 - 20 = 116 degrees.
m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.
Answer:
The answer is 4 hours and 49 minutes
Step-by-step explanation:
Answer:
Symmetric point: x = -1; (-1, 5)
Minimum of f: None; approaches -∞.
Maximum of f: y = 5.
Is f(x) a one-to-one: No, it fails the horizontal line test and is not injective.
Increasing from: -∞ to -1; (-∞, -1)
Decreasing from: -1 to ∞. (-1, ∞)
Answer:
7x + 8
Step-by-step explanation:
2×2+7x+4
4 + 7x + 4
7x + 8
