Question

Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise at least $400 from the play. Write and graph an inequality for the number of tickets the theater club needs to sell. If the club sells 40 tickets in advance, how many tickets do they need to sell at the door to reach their goal?
Please help and show how to do this work. Thank you!

Answer 1

Your equation should be
$4(40 tickets) + $5(X) = $400
160 +5x = 400
-160            -160
   0     5x =  340
  divide both sides by 5
5x/5 = 340/5
x = 68

so they need to sell 68 tickets at the door.

4(40) + 5(68) = 400
160 + 340  + 400
400 + 400

Answer 2

Answer:

Step-by-step explanation:

Let us notice that the questioner had put the words "at least" in their problem; so this would be an inequality problem.

Let us say x represents the number of tickets sold at the door and y is the number of tickets sold in advance.

If this is so, your problem should be;

5x+4(40)≥400

1. Distribution; 5x+160≥400

2. Subtract 160 from both sides; 5x+160-160≥400-160

3. you are left with; 5x≥240

4. divide 5 from both sides; 5x/5≥240/5

5. you are left with; x ≥ 48

Meaning; they need to sell 48 or more tickets at the door to reach their goal of $400.