![\sf {a}^{2} = {13}^{2} - {5}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%7Ba%7D%5E%7B2%7D%20%20%3D%20%20%7B13%7D%5E%7B2%7D%20%20-%20%20%7B5%7D%5E%7B2%7D%20)
Formula :
Base²= Hypotenuse² - Perpendicular ²
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a}^{2} = {13}^{2} - {5}^{2}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%5E%7B2%7D%20%20%3D%20%20%7B13%7D%5E%7B2%7D%20%20-%20%20%7B5%7D%5E%7B2%7D%20)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a}^{2} =169 - 25](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%5E%7B2%7D%20%20%3D169%20-%2025)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a}^{2} =144](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%5E%7B2%7D%20%20%3D144)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a} = \sqrt{144}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%20%3D%20%5Csqrt%7B144%7D%20)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a} = \sqrt{12 \times 12}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%20%3D%20%5Csqrt%7B12%20%5Ctimes%2012%7D%20)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\hookrightarrow\sf {a} = 12](https://tex.z-dn.net/?f=%20%5Chookrightarrow%5Csf%20%7Ba%7D%20%3D%2012)
Remember the a² in formula has nothing to do with the a we have to find. :)
Answer:
102 feet of fencing.
Step-by-step explanation:
Since this is asking to <u> enclose </u> the yard, it is a perimeter question.
22.5 x 2 = 45
28.5 x 2 = 57
45 + 57 = 102
102 is your answer.
Hope this helps.
Answer:
Step-by-step explanation:
54 / 6= 9
9 points per minute
Add 4 to boh sides
t/5+4-4=9+4
t/5+0=13
t/5=13
times 5/1 both sides
5t/5=5*13
1t=65
t=65
Answer:
Three-fifths
Step-by-step explanation:
The number of sections is 5 and the unshaded section is 3 even numbers are 1, 3 and 5. Since 3 is in both cases there are 3 numbers: 1, 3 and 5. So it is three-fifths