Answer:
30 meters away
Step-by-step explanation:
each second is equal to 5 meters, hence meters per second
Answer:
x = 2, x = -6
Step-by-step explanation:

Subtract 8 from both sides.

Simplify.

Solve with quadratic formula.
a = 1
b = 4
c = -12
I do not have time to show work for quadratic formula parts.
I am so sorry for this inconvenience.
Answer:
The maximum value of C is 68
Step-by-step explanation:
we have the following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Find out the area of the feasible region, using a graphing tool
The vertices of the feasible region are
(0,0),(5,19),(5,0)
see the attached figure
To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results

For (0,0) -----> 
For (5,19) -----> 
For (5,0) -----> 
therefore
The maximum value of C is 68
The graph can be divided into two shapes. A rectangle and a right triangle.
The distance that the rover will cover if it completes one circuit can be computed using the Pythagorean theorem and adding the sides of the rectangle.
Rectangle:
Width = 4 - 2 = 2 meters
Length = 11 - 2 = 9 meters
Triangle = 16 - 2 = 14 ; 14 - 2 = 12 meters (this is the short leg)
long leg of the triangle = length of the rectangle = 9 meters.
12² + 9² = c²
144 + 81 = c²
225 = c²
√225 = √c²
15 = c
Point A to B = 4 - 2 = 2 meters
Point B to C = 15 meters
Point C to D = 16 - 2 = 14 meters
Point D to A = 11 - 2 = 9 meters
Total distance traveled = 2 + 15 + 14 + 9 = 40 meters.
The answer is C The distance between the points (15,6) and (21,22)