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nata0808 [166]
3 years ago
10

Find the measure of the following angles. m < LPM: m m HELP ASAP‼️

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0

Answer:

kpl- 90°

jpk-52°

npm-142°

lpm-38°

Step-by-step explanation:

Margaret [11]3 years ago
8 0

Answer:

m < LPM = 38 degrees

Step-by-step explanation:

For this, you need to use the lines given!

JPN = 38 degrees

Therefore LPM = 38 degrees since it is equal!

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If an airplane in a 1/4in. Scale drawing is 5in. Long, how long is the actual airplane?
dsp73

Answer:

20 in

Step-by-step explanation:

you'd just multiply the length of the airplane by 4

7 0
3 years ago
I NEED HELP FASTTT D:
Doss [256]

Answer:

12x + 15 = 12x - 15

Step-by-step explanation:

-5x - 25 = 5x + 25

-25 = 10x + 25

-50 = 10x

-5 = x

12x + 15 = 12x - 15

15 = -15  ( No solution )

12x + 15 = 3(4x + 5)

12x + 15 = 12x + 15

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7x + 21 = 21

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2 years ago
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Klio2033 [76]

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51%

Step-by-step explanation:

Add up the tallies, as follows:  17+24+9+19.  Then divide the "cycling" tally (24) by this sum ( 69), obtaining the "observed probability that the customer will want to cycle"):  p = 24/69 = 34.7%.

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3 years ago
Find the integration of (1-cos2x)/(1+cos2x)
slega [8]

Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

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It can be written as:

I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

I=\int \sec^2xdx-\int 1dx

I=\tan x-x+C

Therefore, the integration of \dfrac{1-\cos 2x}{1+\cos 2x} is I=\tan x-x+C.

8 0
2 years ago
-9+-5x please help meee cause I'm not Finna fail
Westkost [7]

Answer:

-9-5x

Step-by-step explanation:

they aren't the same because of the variable on 5x. You can simplify the problem to -9-5x but that's about it unless it equals something.

7 0
3 years ago
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