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3 years ago

I have a really bad grade in Geometry right now and I

Mathematics

1 answer:

Andrews [41]3 years ago

4 0

Answer: A. (x - 4, y - 2)

B. (x + 7, y - 11)

Step-by-step explanation:

A) How do you get the x-coordinate of 3 to become a x-coordinate of -1? by subtracting 4 --> x - 4

How do you get the y-coordinate of 5 to become a y-coordinate of 3? by subtracting 2 --> y - 2

The transformation is: (x - 4, y - 2)

B) How do you get the x-coordinate of -4 to become an x-coordinate of 3? by adding 7 --> x + 7

How do you get the y-coordinate of 11 to become a y-coordinate of 0? by subtracting 11 --> y - 11

The transformation is: (x + 7, y - 11)

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X2 + x - 6 = 0 A. -2, -3 B. -2, 3 C. 2, -3 D. 2, 3

kicyunya [14]

the answer is.... C (2,-3)

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4 years ago

Choose the symbol that compares the fractions 4/3 and 7/6 <,>,=

gulaghasi [49]

In order to compare them they need to have the same denominator. Which is 6

Multiply 4/3 by 2/2. You get 8/6

8/6>7/6

4/3>7/6

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3 years ago

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On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,

erastova [34]

Answer:

The distribution of X is normal

$P(X < 1.4) = 0.12654$

$P(X > 3.5) = 0.36051$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ hours$

The standard deviation is $\sigma = 1.4 \ hours$

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

Generally the probability that the child spend less than one hour in a day is mathematically represented as

$P(X < 1.4) = P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma} )$

Here $\frac{X - \mu}{\sigma } = Z (The\ standardized\ value\ of\ X)$

$P(X < 1.4) = P(Z < \frac{1.4 - 3.0}{1.4} )$

$P(X < 1.4) = P(Z < -1.1429 )$

From the z-table the value of

$P(Z < -1.1429 )=0.12654$

So $P(X < 1.4) = 0.12654$

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

$P(X > 3.5) = P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma} )$

$P(X > 3.5) = P(Z > \frac{3.5 - 3.0}{1.4} )$

$P(X > 3.5) = P(Z > 0.3571 )$

From the z-table the value of

$P(Z >0.3571 )=0.36051$

So $P(X > 3.5) = 0.36051$

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3 years ago

HELPPPP!! I’m so lost so please help

WARRIOR [948]

C. 7.8 feet is round your answer to the tenths place.

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3 years ago

What is 3 divided by c

Nina [5.8K]

Answer:

1.00069229 × 10-8 s / m

Step-by-step explanation:

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3 years ago

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