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Scorpion4ik [409]
3 years ago
8

Based on these results, express the probability that the next customer will pay with something other than a credit card as a fra

ction in simplest form.

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer: 99/130

Payment made by any method except credit card is 95+4=99 and altogether there is three payment method including a credit card which sums up to 130.

So the probability is 99/130.

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adell [148]
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Give answer for this question ❓​
rjkz [21]

Answer:

A. True

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Step-by-step explanation:

B is false because rational numbers have either repeating decimals or numbers that come to an end.

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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Find the sum of all the factors of 32 that are multiples of 4
pshichka [43]
Well all the factors of 32 are 1 and 32, 2 and 16, 4 and 8.
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3 years ago
Read 2 more answers
Help plis and thank you<br><br> Find the value of x in the triangle shown below​
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Answer:

61.31

Step-by-step explanation:

By using sinus rule

5 0
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