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3 years ago

Could I get some help? Its simplifying square roots of negative numbers.

Mathematics

1 answer:

Ainat [17]3 years ago

8 0

Answer:

The square root of -100 is 10i.

Step-by-step explanation:

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What the answer.....

Sliva [168]

Your right, the answer is pig:snort, because it is saying what sound the pig makes, just like snake:hiss is saying what sound the snake makes.

6 0

3 years ago

Read 2 more answers

I have to get this so I pass help plz

pshichka [43]

Answer:

$\boxed{\sf x=-2}$

$\boxed{\sf y=-4}$

Step-by-step explanation:

First, Let's solve for x in -2x+2y=-4:

$\sf -2x+2y=-4$

Subtract 2y from both sides:

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

Divide both sides by -2:

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

$\bold{ x=y+2}$

Now, we'll substitute x=y+2 to 3x+3y=-18:

$\sf 3x+3y=-18$

→ let x=2+y

$\sf 3\bold{(2+y)}+3y=-18$

Simplify:

$\sf 6+6y=-18$

Now, let's solve for y in 6+6y=-18

$\sf 6+6y=-18$

Subtract 6 from both sides:

$\sf 6+6y-6=-18-6$

$\sf 6y=-24$

Divide both sides by 6:

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

Now, substitute y=-4 into x=2+y:

$\sf x=2+y$

→ let y = -4

$\sf x=2+\bold{-4}$

$\bold{x=-2}$

Therefore, x=-2 and y=-4.

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5 0

2 years ago

-8(r-2)=40 what is the answer to this equation

Elena-2011 [213]

The answer is r=-3. You use the distributive property which is basically multiplying -8 with all the numbers inside the parenthesis. So -8 x r and -8 x -2. This results to -8r+16=40 (Two negative numbers multiplied together will form a positive number). We use inverse operations to subtract 16 from both sides. 16-16 is 0 and 40-16 is 24. So we are left with -8r=24. We want to be left with only r, so we once again use inverse operations to divide -8 from both sides. -8/-8 is 1, and 24/-8 is -3. So we end up with r=-3. Hope this helped :]

6 0

3 years ago

Can someone please help me with this one question please??

Alenkasestr [34]

((5x2)+5.5+(6x3)+6.5+(7x5)+(7.5x4)+(8x4))/20
137/20
= 6.85

5 0

3 years ago

For how many positive values of n are both n3 and 3n four-digit integers?

AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

$n^3 , 3^n$ our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0

3 years ago

Could I get some help? Its simplifying square roots of negative numbers.​

Could I get some help? Its simplifying square roots of negative numbers.