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nika2105 [10]
3 years ago
11

Could I get some help? Its simplifying square roots of negative numbers.​

Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Answer:

The square root of -100 is 10i.

Step-by-step explanation:

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8 0
2 years ago
Tara is the editor of the school newspaper. She tries to devote about 1/2 of the paper to news, 1/3 to pictures, and the remaind
Klio2033 [76]
5/6 of the paper is devoted to news and pictures

first I made the fraction have equal denominators which was 6 by doing that I multiplyed the numerator and the denominator

1/2
1×3=3
2×3=6
therefore 1/2 being equivalent to 3/6


1/3
1×2=2
3×2=6
therefore 1/3 being equivalent to 2/6

now you would be able to add the numerators, so 2+3=5
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4 0
3 years ago
At the movies, tickets for a night show cost $9, and tickets for a day show cost $6.75. What percent is the discount you get for
Nadya [2.5K]
I think it is 3.25%. That is what I had got when I had did my math

8 0
3 years ago
Find the measure of the exterior angle X:<br> 125
igomit [66]
Answer: x=80°

Explanation:
To find the exterior angle x we first need to find the last corner angle (a) of the triangle. The angles of triangles add up to 180° so we can use the formula: 25+55+a=180

Solving formula:
25+55+a=180
80+a=180
(Subtract 80 from both sides)
a=100°

Now that we know a=100 we can find the exterior angle. a+x=180 because the angles are on a straight line which equals 180°

a+x=180
100+x=180
(Subtract 100 from both sides)
x=80°

Hope this helps! Please leave a thanks if possible so I can continue to help others :)
5 0
3 years ago
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

___

Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

__

Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

_____

The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

__

The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
3 years ago
Read 2 more answers
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