|2x + 6| - 4 = 20
First, add 4 to both sides. / Your problem should look like: |2x + 6| = 20 + 4
Second, simplify 20 + 4 to 24. / Your problem should look like: |2x + 6| = 24
Third, break down the problem into these 2 equations. / 2x + 6 = 24 and -(2x + 6) = 24
Fourth, solve the 1st equation: 2x + 6 = 24
Subtract 6 from both sides. / Your problem should look like: 2x = 24 - 6
Simplify 24 - 6 to 18. / Your problem should look like: 2x = 18
Divide both sides by 2. / Your problem should look like: x =

Simplify

to 9 / Your problem should look like:
x = 9
Fifth, solve the 2nd equation: -(2x + 6) = 24
Simplify brackets. / Your problem should look like: -2x - 6 = 24
Add 6 to both sides. / Your problem should look like: -2x = 24 + 6
Simplify 24 + 6 to 30. / Your problem should look like: -2x = 30
Divide both sides by -2. / Your problem should look like: x =

Simplify

to

/ Your problem should look like: x =

Simplify

to 15. / Your problem should look like:
x = -15
Sixth, collect all of your solutions. / Your problem should look like: x = -15, 9
Answer:
x = -15, 9 (C)
To divide complex numbers in polar form, divide the r parts and subtract the angle parts. Or
<span><span><span><span>r2</span><span>(<span>cos<span>θ2 </span>+ i</span> sin<span>θ2</span>) / </span></span><span><span>r1</span><span>(<span>cos<span>θ1 </span>+ i</span> sin<span>θ1</span>)</span></span></span></span> <span>= <span><span><span>r2/</span><span>r1</span></span></span><span>(cos(<span><span>θ2</span>−<span>θ1) </span></span>+ i sin(<span><span>θ2</span>−θ1)</span><span>)
</span></span></span>
z1/z2
= 3/7 (cos(π/8-π/9) + i sin(π/8 - π/9))
= 3/7 (cos(π/72) + i sin(π/72))
I need help to find the root?
Answer: y = 4x -1
Step-by-step explanation:
Given by the graph.
Y axis
and rise over run.