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avanturin [10]
3 years ago
12

(please help!) Two buses leave the bus station at 8 am. If Bus #1 makes its route in a total of 60 minutes and Bus #2 makes its

route in a total of 80 minutes, at what time will the two buses meet again?
Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

  12 pm noon

Step-by-step explanation:

The least common multiple of the two times is 240 minutes, or 4 hours. The buses will meet at the station again at noon.

__

60 = 20×3

80 = 20×4

The least common multiple is 20×3×4 = 240 minutes. There are 60 minutes in an hour, so this is 240/60 = 4 hours. 4 hours after 8 am is 12 pm, noon.

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<u>Given expression</u>

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Simplify values in the parenthesis

\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }

\large\boxed{=\frac{12[5]}{|10|-|-6| } }

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\large\boxed{=\frac{12[5]}{10-6 } }

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\huge\boxed{\boxed{=15}}

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