1. X + 5
2.15-15
3. C= ( 3x9.95)+(2x14.98)
4.?
5. 12,000+500x ?idk
No they wont have the same amount of money ana has more than jose and he’s spending more and wont have enough for the whole week, while ana will have enough and she’s only wasting 4$....
Let us bear in mind the equivalent value of these coins:
One dime = $0.10
One quarter = $0.25
Let x = number of dimes
y<span> = number of quarters</span>
Since the boy has 70 coins in total, we can say that:
<span>x + y = </span><span>70 </span>(can be written as x = 70 – y)
Since the boy has a total of $12.40, we can say that:
0.10x + 0.25y = 12.40
To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)
0.10(70 – y) + 0.25y = 12.40
7 – 0.10y + 0.25y = 12.40
0.15y = 5.40
y = 36
X = 70 – 36
X = 34
Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span>
34 dimes = $3.40
36 dimes = $9.00
<span>Total </span><span>$12.40</span>
Y - y1 = m(x - x1)
slope(m) = -3/7
(5,8)...x1 = 5 and y1 = 8
now we sub
y - 8 = -3/7(x - 5) <===
B. 6.3 Because, for a triangle, you can use the angles to figure out the length. You can also tell that it can’t be D or A because it’s not longer than the base and it’s not small enough to be C.
