Well, if there are 3 sheep for every 8 horses then there should be 15.75 sheep.

.......you divide 42 by 8 to find the number of horses (5.25) and then multiply that by 3 (15.75).

I hope this helps you.

3 0

2 years ago

30000 at 8% per year for 10 months equals to

motikmotik

Answer:

2000

Step-by-step explanation:

S.I=P×rate / 100×time

30000×8 / 100×5/6

=2000

3 0

3 years ago

What is the answer?<br> 82.7(blank)<br> - 5.59<br> ----------

Goshia [24]

The answer will be 77.11

3 0

3 years ago

Read 2 more answers

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

3 years ago