Hello :
the equation 3x^2+4x-7=0 has 2 solutions because : ac <span>< 0
a = 3 b=4 c= -7
</span>Δ = b²-4ac....... b² ≥ 0 and -4ac > 0 ..... (ac < 0 )
coclusion : Δ>0.....(2 solutions)
Answer:
x + y = 5
<u>3x - 4y = 8</u><u> </u><u> </u><u> </u>
3x + 3y = 15
<u>3x - 4y = 8 </u>-
7y = 7
y = 1
x + y = 5
x + 1 = 5
x = 4
x = 4
y = 1
Hope it helps!
Answer: Second option is correct.
Explanation:
Since we have given that

And 
To find the remainder, we use the Remainder Theorem, which states that when f(x) is divided by (x-c) then the f(c) is the required remainder.
So,
Here, we have,

So, we will find f(-2) which will give us the required remainder,

Hence, Second option is correct.
It’s is 82 because you are supposed to do multiply first then add it witch does 82