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AlladinOne [14]
3 years ago
8

The graph shows the distance y, in inches, a pendulum moves to the right (positive displacement) and to the left (negative displ

acement), for a given number of seconds x. How many seconds are required for the pendulum to move from its resting position and return?

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

1 second

Step-by-step explanation:

1.5 seconds - 0.5 seconds = 1 second

ddd [48]3 years ago
5 0

Answer:

<h2>1 second.</h2>

Step-by-step explanation:

The graph is showing a periodic movement, which is the case of the movement of a pendulum. The x-axis represents the equilibrium point, that is y=0. So, each extreme point is where the pendulum immediately stops an return, So, we just have to observe what time it takes intercepting the axis twice in a row.

So, we see that at x=0.5, the pendulum is at equilibrium point, then at x=1.5 is crossing immediately again the equilibrium point. The time that took from 0.5 to 1.5 is 1 second, that is, 1.5-0.5 = 1 second.

Therefore, it takes 1 second to move from its resting point and return.

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WILL MARK THE BRAINLIEST!! PLEASE HELP If ∠1 = 3x, ∠2 = 5x + 18, and s ⊥ r, find m∠1. Question 5 options: A) 27° B) 63° C) 61° D
Yakvenalex [24]

Answer:

A. 27°

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Given that s is perpendicular to r, and <1 = 3x, <2 = 5x + 18, therefore:

m<1 + m<2 = 90°

3x + (5x + 18) = 90°

Solve for x using this equation

3x + 5x + 18 = 90

8x + 18 = 90

Subtract 18 from both sides

8x + 18 - 18 = 90 - 18

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x = 9

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