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AlladinOne [14]
3 years ago
8

The graph shows the distance y, in inches, a pendulum moves to the right (positive displacement) and to the left (negative displ

acement), for a given number of seconds x. How many seconds are required for the pendulum to move from its resting position and return?

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

1 second

Step-by-step explanation:

1.5 seconds - 0.5 seconds = 1 second

ddd [48]3 years ago
5 0

Answer:

<h2>1 second.</h2>

Step-by-step explanation:

The graph is showing a periodic movement, which is the case of the movement of a pendulum. The x-axis represents the equilibrium point, that is y=0. So, each extreme point is where the pendulum immediately stops an return, So, we just have to observe what time it takes intercepting the axis twice in a row.

So, we see that at x=0.5, the pendulum is at equilibrium point, then at x=1.5 is crossing immediately again the equilibrium point. The time that took from 0.5 to 1.5 is 1 second, that is, 1.5-0.5 = 1 second.

Therefore, it takes 1 second to move from its resting point and return.

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Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

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Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

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b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

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