I need to know how the find the value of x

Quinton answered 90% of his test questions correctly. Quinton answered 54 questions correctly.

snow_tiger [21]

There would be 60 questions on the test.

90%=54
1%= 54/90 = 6/10
100%= 6×100/10 =6×10=60

7 0

2 years ago

B

balandron [24]

Answer: (2x + 3) • (x-1)

Step-by-step explanation:

1 Pull out like factors :

4x + 6 = 2 • (2x + 3)

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

(5x - 5) = 5 • (x - 1)

5 0

2 years ago

Please help me I’ve asked this questions several times and I really need help with this I do not understand it at all

Ulleksa [173]

Answer:

(-5,-2)

(-4,-3)

(-6,-1)

Step-by-step explanation:

-5(x)-2(y)=-7

-4(x)-3(y)=-7

-6(x)-1(y)=-7

6 0

2 years ago

The measure of an angle is 6°. What is the measure of its complementary angle?

stealth61 [152]

Answer:

84 degrees.

Step-by-step explanation:

First, let's define what a complementary angle is. It's when two angles add up to 90 degrees. So we do 90-6=84 and 84+6 does in fact equal 90, so they are complementary.

5 0

3 years ago

Read 2 more answers

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago