can you imagine a situation that you can model using two equations such as c= p+0.06p=1.06p and f=c-50?
1 answer:
Answer:
If you are on Connexus this test is a reflection so there is no wrong answers.
Step-by-step explanation:
You might be interested in
Hello,
![\sqrt{x} - \sqrt{y} = (\sqrt[4]{x}+ \sqrt[4]{y} )( \sqrt[4]{x} - \sqrt[4]{y} )=72\\\\ \sqrt[4]{x}- \sqrt[4]{y}=6\\\\ (\sqrt[4]{x}+ \sqrt[4]{y})*6=72\\\\ \sqrt[4]{x}+ \sqrt[4]{y}=12 \\ \sqrt[4]{x}- \sqrt[4]{y}=6 \\\\ 2 \sqrt[4]{x}=18==\textgreater\sqrt[4]{x}=9==\textgreater\ x=6561\\ 2 \sqrt[4]{y}=6==\textgreater\sqrt[4]{y}=3==\textgreater\ y=81\\ ](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20-%20%5Csqrt%7By%7D%20%3D%20%28%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%20%29%28%20%5Csqrt%5B4%5D%7Bx%7D%20-%20%5Csqrt%5B4%5D%7By%7D%20%29%3D72%5C%5C%5C%5C%0A%5Csqrt%5B4%5D%7Bx%7D-%20%5Csqrt%5B4%5D%7By%7D%3D6%5C%5C%5C%5C%0A%28%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%29%2A6%3D72%5C%5C%5C%5C%0A%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%3D12%20%5C%5C%20%0A%5Csqrt%5B4%5D%7Bx%7D-%20%5Csqrt%5B4%5D%7By%7D%3D6%20%5C%5C%5C%5C%0A2%20%5Csqrt%5B4%5D%7Bx%7D%3D18%3D%3D%5Ctextgreater%5Csqrt%5B4%5D%7Bx%7D%3D9%3D%3D%5Ctextgreater%5C%20x%3D6561%5C%5C%0A2%20%5Csqrt%5B4%5D%7By%7D%3D6%3D%3D%5Ctextgreater%5Csqrt%5B4%5D%7By%7D%3D3%3D%3D%5Ctextgreater%5C%20y%3D81%5C%5C%0A%0A%0A%20)
Proof:
Answer:
56, Below.
Step-by-step explanation:
75/4+37 As you plug this into the formula you get 56.66(Something) And round it to 56.
Answer:
a) £6.70 b)6.4%
Step-by-step explanation:
a) 105.20-98.50=6.70
b)105.20-98.50/105.20 x100= 6.4%
i hope i got it right welp
68Answer:
10
Step-by-step explanation:
68/2=34
24+10=34
16. PM = 26x + 8x^2y
A = 52x^3y
17. Area = 33a^5b