Answer:
The unit cell edge length is 393.21 pm.
The density of platinum is
Step-by-step explanation:
Number of atom in FCC unit cell = Z = 4
Density of platinum =
Edge length of cubic unit cell= a= ?
Radius of the platinum atom, r = 139 pm
r = 0.3535 a
Atomic mass of Pt(M) = 195.08 g/mol
Formula used :
where,
= density
Z = number of atom in unit cell
M = atomic mass
= Avogadro's number
a = edge length of unit cell
On substituting all the given values , we will get the value of 'a'.
.
The unit cell edge length is 393.21 pm.
The density of platinum is .