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Eva8 [605]
3 years ago
12

Four polynomials are shown below:

Mathematics
1 answer:
Sloan [31]3 years ago
3 0
I think it is NO. C. I holp it is help.
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Using a standard six-sided die, janice rolled either a 2 or a 5on the last 6 rolls of the die. what is the probability of janice
Vedmedyk [2.9K]

Answer:

1/3

Step-by-step explanation:

probability = favorable outcomes/total possible outcomes

There are two favorable outcomes, 2 and 5.

There are 6 total possible outcomes.

Make your fraction.

2/6

reduce

1/3

8 0
2 years ago
Help please i need help
Anika [276]

Answer:

OMG what level is this???

Step-by-step explanation:


8 0
3 years ago
All side lengths of ΔJKL equal 2 units. A transformation maps ΔJKL to ΔJ'K'L'. The length of side J'K' is 5 units. Is this a rig
S_A_V [24]
No because at least one segment length is not preserved.
rigid means everything stays the same, but orientation sometimes changes.
5 0
3 years ago
Read 2 more answers
A test was marked out of 80. A boy scored 60% of the marks on the test. How many marks did he score?
cricket20 [7]
He score 48 marks.

This can be found by simply multiplying 80 by 60% (0.6). This will give you your rinal answer of 48.

I hope this helps!
7 0
3 years ago
The height of one right circular cylinder is 6 centimeters and its radius is 3 centimeters. The height of a second right circula
melomori [17]

Answer:

<h3>The volume of the second cylinder is three times as large as the volume of the first cylinder .</h3><h3>Hence V_2=3\times V_1</h3>

Step-by-step explanation:

Given that the height of one right circular cylinder is 6 centimeters and its radius is 3 centimeters.

Let h_1,r_1 be the height and radius of the first right circular cylinder respectively.

∴ h_1=6 cm and r_1=3 cm

The height of a second right circular cylinder is 18 centimeters and its radius is 3 centimeters.

Let h_2,r_2 be the height and radius of the second right circular cylinder respectively.

∴ h_1=18 cm and r_1=3 cm

<h3>To find the volume of the second cylinder is how many times as large as the volume of the first cylinder :</h3>

The formula for Volume of right circular cylinder is

V=\pi r^2h units

The  Volume of first right circular cylinder is

V_1=\pi r_1^2h_1

Substitute the values in the formula we get

V_1=\pi (3^2)(6)

V_1=\pi (9)(6)

=54\pi units

∴ V_1=54\pi units

The  Volume of second right circular cylinder is

V_2=\pi r_2^2h_2

Substitute the values in the formula we get

V_2=\pi (3^2)(18)

V_2=\pi (9)(18)

=162\pi units

∴ V_2=162\pi units

From the volumes V_1 and V_2 we get

\frac{V_2}{V_1}=\frac{162\pi}{54\pi}

=3

\frac{V_2}{V_1}=3

∴ V_2=3\times V_1

<h3>The volume of the second cylinder is three times as large as the volume of the first cylinder .</h3>
8 0
3 years ago
Read 2 more answers
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