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3 years ago

Four polynomials are shown below:

Mathematics

1 answer:

Sloan [31]3 years ago

3 0

I think it is NO. C. I holp it is help.

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Using a standard six-sided die, janice rolled either a 2 or a 5on the last 6 rolls of the die. what is the probability of janice

Vedmedyk [2.9K]

Answer:

1/3

Step-by-step explanation:

probability = favorable outcomes/total possible outcomes

There are two favorable outcomes, 2 and 5.

There are 6 total possible outcomes.

Make your fraction.

2/6

reduce

1/3

8 0

2 years ago

Help please i need help

Anika [276]

Answer:

OMG what level is this???

Step-by-step explanation:

8 0

3 years ago

All side lengths of ΔJKL equal 2 units. A transformation maps ΔJKL to ΔJ'K'L'. The length of side J'K' is 5 units. Is this a rig

S_A_V [24]

No because at least one segment length is not preserved.
rigid means everything stays the same, but orientation sometimes changes.

5 0

3 years ago

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A test was marked out of 80. A boy scored 60% of the marks on the test. How many marks did he score?

cricket20 [7]

He score 48 marks.

This can be found by simply multiplying 80 by 60% (0.6). This will give you your rinal answer of 48.

I hope this helps!

7 0

3 years ago

The height of one right circular cylinder is 6 centimeters and its radius is 3 centimeters. The height of a second right circula

melomori [17]

Answer:

<h3>The volume of the second cylinder is three times as large as the volume of the first cylinder .</h3><h3>Hence $V_2=3\times V_1$ </h3>

Step-by-step explanation:

Given that the height of one right circular cylinder is 6 centimeters and its radius is 3 centimeters.

Let $h_1,r_1$ be the height and radius of the first right circular cylinder respectively.

∴ $h_1=6 cm$ and $r_1=3 cm$

The height of a second right circular cylinder is 18 centimeters and its radius is 3 centimeters.

Let $h_2,r_2$ be the height and radius of the second right circular cylinder respectively.

∴ $h_1=18 cm$ and $r_1=3 cm$

<h3>To find the volume of the second cylinder is how many times as large as the volume of the first cylinder :</h3>

The formula for Volume of right circular cylinder is

$V=\pi r^2h$ units

The Volume of first right circular cylinder is

$V_1=\pi r_1^2h_1$

Substitute the values in the formula we get

$V_1=\pi (3^2)(6)$

$V_1=\pi (9)(6)$

$=54\pi$ units

∴ $V_1=54\pi$ units

The Volume of second right circular cylinder is

$V_2=\pi r_2^2h_2$

Substitute the values in the formula we get

$V_2=\pi (3^2)(18)$

$V_2=\pi (9)(18)$

$=162\pi$ units

∴ $V_2=162\pi$ units

From the volumes $V_1 and V_2$ we get

$\frac{V_2}{V_1}=\frac{162\pi}{54\pi}$

$=3$

$\frac{V_2}{V_1}=3$

∴ $V_2=3\times V_1$

<h3>The volume of the second cylinder is three times as large as the volume of the first cylinder .</h3>

8 0

3 years ago

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