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WINSTONCH [101]
2 years ago
11

Solve for a and b (6a-3)=(7b-10)

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
3 0

Answer:

for A=\frac{7b-7}{6} and for B=\frac{6a+7}{7}

Step-by-step explanation:

For A

\left(6a-3\right)=\left(7b-10\right)

6a-3+3=7b-10+3

6a=7b-7

\frac{6a}{6}=\frac{7b}{6}-\frac{7}{6}

a=\frac{7b-7}{6}

For B

\left(6a-3\right)=\left(7b-10\right)

7b-10=\left(6a-3\right)

7b-10=6a-3

7b-10+10=6a-3+10

7b=6a+7

\frac{7b}{7}=\frac{6a}{7}+\frac{7}{7}

b=\frac{6a+7}{7}

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9. Triangle Construction pays Square Insurance $5,980
xxTIMURxx [149]

The triangle pay $32 more for that day than it paid per day during the first period of time.

Step-by-step explanation:

The given is,

              Triangle Construction pays Square Insurance $5,980

               To insure a construction site for 92 days

               To extend the  insurance beyond the 92 days costs $97 per day

               Triangle extends the insurance by 1 day

Step:1

              Insurance per day from the 92 days period,

                                                                           = \frac{Total insuratio for 92 days}{Period}

               Where, Total insurance for 92 days = $ 5,980

                                                               Period = 92 days

               From the values, equation becomes,

                                                                            =\frac{5980}{92}

                                                                           = $ 65 per day

Step:2

              Insurance per day after the 92 days,

                                                                           = $ 97

               Amount Pay for that day than it paid per day during the first period of time,

                                                                            =(97-65)

                                                                           = $32

Result:

             The triangle pay $32 more for that day than it paid per day during the first period of time, if  the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the  insurance beyond the 92 days costs $97 per day.

                                                                         

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