Question

Solve for a and b (6a-3)=(7b-10)

Answer 1

Answer:

for A=$\frac{7b-7}{6}$ and for B=$\frac{6a+7}{7}$

Step-by-step explanation:

For A

$\left(6a-3\right)=\left(7b-10\right)$

$6a-3+3=7b-10+3$

$6a=7b-7$

$\frac{6a}{6}=\frac{7b}{6}-\frac{7}{6}$

$a=\frac{7b-7}{6}$

For B

$\left(6a-3\right)=\left(7b-10\right)$

$7b-10=\left(6a-3\right)$

$7b-10=6a-3$

$7b-10+10=6a-3+10$

$7b=6a+7$

$\frac{7b}{7}=\frac{6a}{7}+\frac{7}{7}$

$b=\frac{6a+7}{7}$