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irina [24]
3 years ago
6

Identify each pair of angles vertical, supplementary, or complementary

Mathematics
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

5. V

6. S

7. V

8. S

9. C

Step-by-step explanation:

Vertical angles: Angles facing each other vertically.

Supplementary angles: Angles that add up to 180 degrees, making a straight line.

Complementary angles: Angles that add up to 90 degrees, making a right angle.

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If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?
Tomtit [17]

Answer:

Sec y = q/r

Step-by-step explanation:

Sin y = 7/q

tan y = 7/r

Mathematically cos y = sin y/tan y

But sec y = 1/cos y

So therefore sec y = tan y/sin y

So that would be ;

7/r divided by 7/q

= 7/r * q/7

= q/r

3 0
3 years ago
Given three positive integers a, b and c such that a² + b² - c² = 1. Let the number of triangles formed with sides a, b and c wi
Akimi4 [234]

Answer:

Step-by-step explanation:

Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)

Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.

Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.

Examples:

Input: N = 10

Output: 2

1^2 + 3^2 = 9

3^2 + 1^2 = 9

Input: N = 8

Output: 1

2^2 + 2^2 = 8

8 0
4 years ago
Jim drove 175 miles in 3 hrs 30 mins.How many miles per hour did Jim drive?
exis [7]
Jim drove 50 miles per hour
8 0
4 years ago
Someone help or nah?
cricket20 [7]

Answer:

25

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2 At Bea's Pet Shop, the number of dogs, d, is initially five less than twice the number of cats, c. If she decides to add three
forsale [732]

Let D be dogs and C be cats

<em>dogs, d, is initially five less than twice the number of cats, c</em>

D + 5 = 2C

<em>If she decides to add three more of each, the ratio  of cats to dogs will be</em>

D + 8 = 2C + 3

<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>

Simply plug in the numbers

20 + 5 = 2(15)

This is clearly not true: 25 does not equal 30

<em />

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7 0
3 years ago
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