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DochEvi [55]
3 years ago
8

A customer asks you over the phone how much it will cost to upgrade memory on her desktop system to 16 GB. She is a capable Wind

ows user and able to access BIOS/UEFI setup using the user power-on password you set up for her. Which actions can you ask the customer to perform as you direct her over the phone to get the information you need and develop an estimate of the upgrade’s cost? a. Use BIOS/UEFI to view how much memory is installed and how much memory the system can hold. b. Enter info32.exe to determine how much memory is currently installed. c. Use BIOS/UEFI to show which memory slots are used and how much memory is installed in each slot. d. View the System Information window to determine how much memory is currently installed.
Computers and Technology
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

b. Enter info32.exe to determine how much memory is currently installed.

Explanation:

The reason is that as an IT expert i'm not supposed to assume the users level of knowledge would be as good as mine so instead I would work the user through a more familiar and straight forward path such as booting to the windows first and then using the info32.exe command in the RUN interface.

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Create a function named first_a that uses a list comprehension. The function will take a single integer parameter n. Find every
aivan3 [116]

Answer:

def first_a(n):

   lst1 =[x for x in range(1,n+1)if x%6==0 or x%11 ==0]

   print(lst1)

Explanation:

Above is a function in python programming language. We have used list comprehension to check numbers that are multiples of 6 or 11 in a range.

When this function is called it will receive an argument (n) of type integer, a range will then be generated from 1 to n+1 since n is inclusive. The modulo operator is used to determine is a value is a multiple of 6 or 11, since their multiples will evaluate to 0

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3 years ago
What is the function of the NOS? Select all that apply.
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Answer:

.network management

Explanation:

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3 years ago
Read 2 more answers
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
3 years ago
The source must decode a message before it can be sent. select one: <br> a. True <br> b. False
Pani-rosa [81]
True because that's what i said it is 
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3 years ago
Use the following data definitions data myBytes BYTE 10h,20h,30h,40h myWords WORD 3 DUP(?),2000h myString BYTE "ABCDE" What will
Elena-2011 [213]

Answer:

<em>Given Data:</em>

<em>myBytes BYTE 10h, 20h, 30h, 40h </em>

<em>myWords WORD 3 DUP(?), 2000h </em>

<em>myString BYTE "ABCDE"</em>

<em />

Based on the data that we are given we can conclude that:

(a).     a. EAX = 1

         b. EAX = 4

         c. EAX = 4

         d. EAX = 2

         e. EAX = 4

         f. EAX = 8

         g. EAX = 5

8 0
3 years ago
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