Even numbers are numbers whigh are divisible by 2. Therefore, the first even number is 2. A pseudocode which adds the first 100 even numbers can be written thus :
counter = 0
sum = 0
interval = 2
while counter < 100 :
sum = sum + interval
interval += 2
counter +=1
print(sum)
- A counter takes count of the number of values summed
- Initializes a variable which holds the sum of even values
- Since even numbers are divisible by 2; every factor ; increase every added value by 2
- The program ends once counter is 100
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Answer:
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Alex can use a less formal style, does not have to explain the background in detail, and should get to the point quickly.
<h2>This function will land up in infinite function call</h2>
Explanation:
first time when the function gets invoked,
f(6,8), so k=6 & n=8, inside the function it checks k==n, ie. 6==8, returns false, then one more if is available, so 6>8 is check for , once again it is false and else loop is executed, the function is called recursively using f(k-n,n), that is f(6-8,8), it means f(-2,8) is passed.
Second time,
if(-2==8) is false, so if(-2>8) is again false and function f(-10, 8) is called
if(-10==8) is false, so if(-10>8) is again false and function f(-18,8) is called
if(-18==8) is false, so if(-18>8) is again false and function f(-26,8) is called
So this goes recursively and ends in an infinite function call.