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3 years ago

How many valance Elton’s does aluminum have

Chemistry

2 answers:

Arada [10]3 years ago

7 0

Answer:13

Explanation:On the periodic table of elements 13 is the atomic number,which is the amount of protons and electrons

inn [45]3 years ago

5 0

Actually, the valence electron number for aluminum is 3

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What is true about the number of water particles in the pot after the water has been warmed?

Elza [17]

Answer:ye

Explanation:

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3 years ago

What is the affect of increasing the water's mass?how does it reflect it's temperature?

Nikolay [14]

I assume what you're asking about is, how does the temperature changes when we increase water's mass, according the formula for heat ?
Well the formula is : $Q=m\cdot c\cdot \Delta t$ (where Q is heat, m is mass, c is specific heat and $\Delta t$ is change in temperature. So according this formula, increasing mass will increase the substance's heat, but won't effect it's temperature since they are not related. Unless, if you want to keep the substance's heat constant, in that case when you increase it's mass you will have to decrease the temperature

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3 years ago

How many grams are equivalent to 1.80x10-4 tons?

zloy xaker [14]

Do you want the estimated answer or the exact answer?

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3 years ago

A biological process by which sugars are converted into energy and lactate

elena55 [62]

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3 years ago

Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina

yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

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3 years ago