Answer:
The correct option is: carbon dioxide (CO₂)
Explanation:
Cellular respiration refers to the process of generation of energy in the form of adenosine triphosphate (ATP) from various nutrients such as carbohydrates, fats, and proteins.
Aerobic cellular respiration involves the oxidation of nutrients such as glucose (C₆H₁₂O₆), by molecular oxygen (O₂) to give carbon dioxide (CO₂), water (H₂O) and heat energy.
Reaction involved: (glucose) C₆H₁₂O₆ (s) + 6 O₂ (g) → 6 CO₂ (g) + 6 H₂O (l) + heat energy
<u>Therefore, in a cellular respiration, all the carbon atoms of the glucose molecules, form carbon dioxide.</u>
Answer:
74.09 atm
Explanation:
Using the gas laws ( Charles and Boyle's law). We have the formula ,
P1/T1 = P2/T2
Where P1 = 30.3atm
T1 = -100 degree Celsius
to kelvin = -100+ 273 = 173K
T2 = 150 degree Celsius
To Kelvin = 150 = 150+273 = 423K
Imputing values
P1/T1 = P2/T2
30.3/173 = P2/ 423
Cross multiply
173×P2 = 30.3 ×423
173P2 = 12816.9
Divide both sides by 173
P2 = 12816.9/173
P2 = 74.09 atm
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Answer:
- Part a) 0.0104 moles copper(II) nitrate.
i) 0.0418 mole Cu
ii) 0.0209 mol Ag NO₃
Explanation:
<u>1) Balanced chemical reaction (single replacement):</u>
In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)
- Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag
<u>2) Mole ratio: </u>
- 1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag
<u />
<u>3) Moles of Ag</u>
- n = mass in grams / atomic mass
- atomic mass of Ag: 107.868 g/mol
- n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag
<u>4) Moles of copper(II) nitrate:</u>
- Set the proportion using the mole ratio:
- 2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x
- Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ = 0.0104 moles Cu(NO₃)₂
That is the answer of part a: 0.0104 moles copper(II) nitrate.
<u>5) Moles of each reactant</u>
i) Cu:
- Set a proportion using the theoretical mole ratio
1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag
- Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu
ii) Ag NO₃
- Set a proportion using the teoretical mole ratio
2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag
- Solve for x: x = 0.0209 mol Ag NO₃
Answer:
You must add 48.97 mL of water to make the 0.200 M diluted solution.
Explanation:
In chemistry, dilution is the reduction in concentration of a chemical in a solution. In other words, it is the process of reducing the concentration of solute in solution, simply adding more solvent to the solution.
In a dilution, the quantity or mass of the solute is not changed but only that of the solvent. As only solvent is being added, by not increasing the amount of solute the concentration of the solute decreases.
The expression for the dilution calculations is:
Cinitial* Vinitial = Cfinal* Vfinal
In this case:
- Cinitial= 12 M
- Vinitial= 0.830 mL
- Cfinal= 0.200 M
- Vfinal= ?
Replacing:
12 M*0.830 mL= 0.200 M*Vfinal
Solving:
Vfinal= 49.8 mL
Since 0.830 mL is the volume you initially have of HCl, the amount of water you must add is:
49.8 mL - 0.830 mL= 48.97 mL
<u><em>You must add 48.97 mL of water to make the 0.200 M diluted solution.</em></u>
Answer:
<em>Barometers measure this pressure. ... Changes in the atmosphere, including changes in air pressure, affect the weather. Meteorologists use barometers to predict short-term changes in the weather. A rapid drop in atmospheric pressure means that a low-pressure system is arriving.</em>
Explanation:
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<em>I </em><em>hope</em><em> this</em><em> helps</em><em>!</em></h3>
