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elena-s [515]
3 years ago
9

What is the number of electrons in silicon-30

Chemistry
2 answers:
Mila [183]3 years ago
6 0

Answer:

2, 8, 4

Explanation:

adoni [48]3 years ago
6 0
The number of electrons in silicon-30 is 14
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Which of the following reactions is spontaneous?
AveGali [126]
Answer is: <span>lumps os sugar dissolving in water.
Sugar has very good solubility in water and it dissolves readily, which is </span><span>example of a physical change.
</span>Gibbs free energy (G) determines if reaction will proceed spontaneously, if ΔG is negative, reaction is spontaneous <span>(ΔG = ΔH - T·ΔS).
</span>In other examples, reactions are spontaneous in reverse way, for example spontaneous is forming sodium chlorine from sodium metal and chlorine gas, but not sodium chloride forming sodium metal and chlorine gas, because a lot of energy is needed for that reaction.
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3 years ago
Ascientist is measuring the pressure that is exerted by each of the following gases in the atmosphere: carbon dioxide, oxygen,
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Answer:

Partial pressure

Explanation:

the scientists is measuring different pressure, so it would be partial pressure. Hope that this helps you and have a great day :)

4 0
3 years ago
Which compound has the highest percent composition by mass of strontium
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So if the compound has the smallest gram formula mass it has the highest percentage composition by mass of strontium
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3 years ago
HNO3 + S --&gt; H2SO4 + NO Now identify the element oxidized and the element reduced. Which element is oxidized? Which element i
OleMash [197]

<u>Answer:</u> S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

<u>Explanation:</u>

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

HNO_3+S\rightarrow H_2SO_4+NO

<u>On the reactant side:</u>

Oxidation number of H = +1

Oxidation number of N = +5

Oxidation number of O = -2

Oxidation number of S = 0

<u>On the product side:</u>

Oxidation number of H = +1

Oxidation number of N = +2

Oxidation number of O = -2

Oxidation number of S = +6

As the oxidation number of S is increasing from 0 to +6. Thus, it is getting oxidized. Similarly, the oxidation number of N is decreasing from +5 to +2. Thus, it is getting reduced.

The oxidation numbers of O and H remain the same on both sides of the reaction. Thus, they are neither getting oxidized or reduced.

Hence, S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

3 0
2 years ago
How many atoms of fluoride are there in one molecule of nitrogen trifluoride?
Helga [31]

Answer:

there are three Fluorine atom. This is because Nitrogen give 3 electron away but fluorine can only take 1. So nitrogen gives 1 neutron to 3 fluorine each which makes it a stable compound

6 0
3 years ago
Read 2 more answers
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