How do you write the equation for when C6H12O6 is burned in oxygen gas?
1 answer:
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Answer:
101.2%
Explanation:
Given:
Theoretical yield of the precipitate = 0.914 g
Actual yield of the precipitate = 0.925 g
Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.
Framing in equation form, we have:
Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,
Therefore, the percent yield is 101.2%.