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Len [333]
3 years ago
11

How do you write the equation for when C6H12O6 is burned in oxygen gas?

Chemistry
1 answer:
Nata [24]3 years ago
5 0
C6H12O6 + 6O2 —-> 6CO2 + 6H2O
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g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol
Ronch [10]

Answer:

M=0.0637M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Pb(NO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaNO_3(aq)

Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

n_{Pb^{2+}}=0.904gPbI_2*\frac{1molPbI_2}{461gPbI_2}*\frac{1molPb(NO_3)_2}{1molPbI_2}  *\frac{1molPb^{2+}}{1molPb(NO_3)_2} =1.96x10^{-3}molPb^{2+}

Finally, the resulting molarity in 30.8 mL (0.0308 L):

M=\frac{1.96x10^{-3}molPb^{2+}}{0.0308L}\\ \\M=0.0637M

Regards.

3 0
3 years ago
Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
3 years ago
Your chemistry lab partner is interested in studying how industrial chemicals can pollute the environment. What type of chemistr
Solnce55 [7]

Answer:

I would recommend them becoming an Analytical Chemist because Analytical Chemists examine and identify various elements and compounds to find out the composition, structure, and nature of substances and they determine the concentration of chemical pollutants in soil, water,and air. I would recommend taking inorganic, organic, analytical, and physical chemistry as well as computer science, physics, and environmental science

3 0
3 years ago
Explain why the standard enthalpy of formation () for Cl2 (g) is zero, but its standard entropy is larger than zero.
Galina-37 [17]

The standard enthalpy of formation for chlorine is zero but the standard entropy is larger than 0 because it is the elemental state of chlorine.

The standard enthalpy of formation for chlorine is zero because cl2 is the elemental state of chlorine and it does not require any energy for the formation of the standard state of chlorine.

The entropy of any system cannot be negative. It can only be positive or zero.

The entropy of a system will become zero only at a absolute zero temperature.

That's why the entropy of chlorine in elemental state is more than zero because absolutely zero temperature can't be obtained.

To know more about entropy, visit,

brainly.com/question/6364271

#SPJ4

7 0
1 year ago
Consider the reaction CaCO3(s) --&gt; CaO(s) + CO2(g)
tankabanditka [31]

Answer:

Kc = [CO2], that is to say it is equal to the concentration of CO2

Explanation:

It is a heterogeneous equilibrium since the substances that participate in the reaction are in different phases

In the heterogeneous limestone decomposition reaction:

CaCO3(s) --> CaO(s) + CO2(g)

The equilibrium constants are:

Kc = [CO2(g)]; Kp = PCO2(g); Kc = Kp (R T)^ −(1−0) = Kp (R T)^ −1

The equilibrium situation is not affected by the amount of  solid or liquid, as long as these substances are present.

The equilibrium constant is independent of the  amounts of solids and liquids in equilibrium.

4 0
3 years ago
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