You find the mRNA code complementary to the strand of DNA .
A T G G C T C A A G C T I'm pretty sure
Answer:
Larger islands that are large and close to the mainland are shos lower rate of extinction due to the fact that the species present have more space so there will be more resources available in comparison to smaller islands where limited space and limited resources available.
Extinction is greater on islands isolated due to the unlikelihood of immigration and as it is opposite to the island close to the mainland and competition is more in isolated islands.
The question is incomplete. The complete question is as follows:
Which of the following mutations is most likely to cause a phenotypic change?
A) a duplication of all or most introns
B) a large inversion whose ends are each in intergenic regions
C) a nucleotide substitution in an exon coding for a transmembrane domain
D) a single nucleotide deletion in an exon coding for an active site
E) a frameshift mutation one codon away from the 3' end of the nontemplate strand
Answer: D) a single nucleotide deletion in an exon coding for an active site
Explanation:
Deletion or insertion of a single nucleotide in an axon coding for an active site is called frameshift mutation.
The sequence of codons is read during translation, in order to synthesize a amino acids chain and form a protein from the nucleotide sequence. Frameshift mutations occur when the usual codon sequence is broken by the deletion or addition of one or more nucleotides. For example, if only one nucleotide is removed from the axon sequence during the RNA splicing process, then there will be a disrupted reading frame for all codons before and after the mutation. This may result in several incorrect amino acids being introduced into the protein. Disruption in protein sequence will cause phenotypic change.
Hence, the correct option is D) a single nucleotide deletion in an exon coding for an active site
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Mass<span> is the actual amount of material contained in a body and is measured in kg, gm, etc. Whereas </span>weight<span> is the force exerted by the gravity on that object mg. Note that </span>mass<span> is independent of everything but </span>weight<span> is </span>different<span> on the earth, moon, etc.</span>
Answer:
This question lacks options, options are: Mr. M's cells are depolarizing too easily. Blocking Nat channels will make it harder for them to depolarize, bringing their sensitivity back to normal O Mr. M has too little K* leaving his cells, so we need to block the Nat channels so the Kt channels can stay open and his cells can repolarize properly. Mr. M has too little K* leaving his cells, so we need to block the Nat channels so the Na /K+ ATPase can move Kt out of the cell effectively O Blocking Na* channels cannot help- it will only make his cells fire less, and he already has a weak heartbeat. Mr. M's cells are not repolarizing properly. Blocking Nat channels will help them repolarize normally, bringing their resting potential back to normal.
The correct answer is ''Mr. M's cells are depolarizing too easily. Blocking Na+ channels will make it harder for them to depolarize, bringing their sensitivity back to normal.''
Explanation:
Calcium administration is an emerging treatment modality aimed at restoring the transmembrane electrical gradient of cardiac myocytes. It probably achieves this goal by reducing the resting membrane potential of cells. Calcium antagonizes the effect of hyperkalemia on cardiac conduction, that is, it antagonizes the effects of K on the heart. Its onset of action is immediate, in a few minutes. Calcium gluconate antagonizes the excitability of the cardiac membrane, that is, it decreases the excitability of the membrane and it does not affect serum levels, it is generally accepted that calcium should be administered when there are ECG changes associated with hyperkalemia.
