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Alik [6]
3 years ago
14

Suppose ACT Reading scores are normally distributed with a mean of 21.4 21.4 and a standard deviation of 5.9 5.9 . A university

plans to award scholarships to students whose scores are in the top 9% 9% . What is the minimum score required for the scholarship? Round your answer to the nearest tenth, if necessary.
Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

29.2

Step-by-step explanation:

Mean = 21.4

Standard deviation = 5.9%

The minimum score required for the scholarship which is the scores of the top 9% is calculated using the Z - Score Formula.

The Z- score formula is given as:

z = x - μ /σ

Z score ( z) is determined by checking the z score percentile of the normal distribution

In the question we are told that it is the students who scores are in the top 9%

The top 9% is determined by finding the z score of the 91st percentile on the normal distribution

z score of the 91st percentile = 1.341

Using the formula

z = x - μ /σ

Where

z = z score of the 91st percentile = 1.341

μ = mean = 21.4

σ = Standard deviation = 5.9

1.341= x - 21.4 / 5.9

Cross multiply

1.341 × 5.9 = x - 21.4

7.7526 = x -21.4

x = 7.7526 + 21.4

x = 29.1526

The 91st percentile is at the score of 29.1526.

We were asked in the question to round up to the nearest tenth.

Approximately, = 29.2

Step-by-step explanation:

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A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G. What are the coordinates
I am Lyosha [343]

Given:

A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G.

To find:

The coordinates of point G.

Solution:

Section formula: If a point divide a line segment with end points (x_1,y_1) and (x_2,y_2) in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Point G divide the line segment FH in 8:2. Using section formula, we get

G=\left(\dfrac{8(8)+2(-8)}{8+2},\dfrac{8(6)+2(-2)}{8+2}\right)

G=\left(\dfrac{64-16}{10},\dfrac{48-4}{10}\right)

G=\left(\dfrac{48}{10},\dfrac{44}{10}\right)

G=\left(4.8,4.4\right)

Therefore, the coordinates of point G are (4.8, 4.4).

4 0
3 years ago
The perimeter of UVW is 22 2/1. And VZ = 2 1/2. Find UW and VW.
Cerrena [4.2K]
UW and VW are the same so 9
22.5-4.5= 18 then divide the 18 by 2 so 9
4 0
3 years ago
Read 2 more answers
How do I solve this question ??????
Vlada [557]
Since you have 4 people total splitting the money, you can find the total amount made in the two months by: 184(4)=736
Since you want the total profit in the second month, subtract the total amount by the profit in the first month: 736-438=298
So the answer is $298
3 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
41. Suppose a family drives at an average rate of 60 mi/h on the way to visit relatives and then at an average rate of 40 mi/h o
Afina-wow [57]

Answer:

The answer is below

Step-by-step explanation:

a) Let x represent the time taken to drive to see the relatives and let d be the distance travelled to go, hence:

60 mi/h = d/x

d = 60x

When returning, they still travelled a distance d, since the return trip takes 1 h longer than the trip there, therefore:

40 mi/h = d/(x+1)

d = 40(x + 1) = 40x + 40

Equating both equations:

60x = 40x + 40

60x - 40x = 40

20x = 40

x = 40/20

x = 2 h

The time taken to drive there = x = 2 hours

b) The time taken for return trip = x + 1 = 2 + 1 = 3 hours

c) The distance d = 60x = 60(2) = 120 miles

The total distance to and fro = 2d = 2(120) = 240 miles

The total time to and fro = 2 h + 3 h = 5 h

Average speed = total distance / total time = 240 miles / 5 h = 48 mi/h

5 0
3 years ago
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