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Serggg [28]
3 years ago
13

What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

6, 7, 13, 20, ...

  • It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

As

d = 7-6=1,  d = 13-7=6

As d is not same. Hence, it cannot be an arithmetic sequence.

  • It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

As

r = 7-6=1,  r = 13-7=6

r = \frac{7}{6},  r = \frac{13}{7}

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that:

  • The given sequence 6, 7, 13, 20, ... is a recursive sequence.

Please have a close look that each term is being created by adding the preceding two terms.

For example, the sequence is generated by starting from 1.

     {\displaystyle F_{1}=1

and

     {\displaystyle F_{n}=F_{n-1}+F_{n-2}}

for n > 1.

<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>

<em>Learn more about sequence from brainly.com/question/10986621</em>

<em>#learnwithBrainly</em>

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Please simplify the following trigonometric identity.
lesya692 [45]

<u>Examining the question:</u>

We are given the expression:

\frac{1}{Sec(\alpha)-Tan(\alpha)}

We know from Basic trigonometry that:

Sec(\alpha) = \frac{1}{Cos(\alpha)}

Tan(\alpha) = \frac{Sin(\alpha)}{Cos(\alpha)}

<u>Simplifying the expression:</u>

Replacing these values in the given expression, we get:

\frac{1}{\frac{1}{Cos(\alpha)} -\frac{Sin(\alpha)}{Cos(\alpha)} }

Since the denominator of both the values in the denominator is the same:

\frac{1}{\frac{1-Sin(\alpha)}{Cos(\alpha)} }

We know that \frac{1}{\frac{a}{b} } = \frac{b}{a}, using the same property:

\frac{Cos(\alpha)}{1-Sin(\alpha)}

and we are done!

7 0
2 years ago
Read 2 more answers
The side lengths of a right triangle are 18 cm, 24 cm, and 30 cm. You are asked to find the area of the triangle by using A = 1/
vekshin1

Answer:

1. Use the Adjacent and opposite side (Ignore the Hypotenuse)

Or use HERO'S FORMULA based on the information given

2. Area = 216cm^2

Step-by-step explanation:

There are three to four ways we can go about finding the area of a triangle. And a these would be dependent on the information given about the triangle.

From the question, you said the three side lengths are given. In such case, we employ the HERO FORMULA.

HERO FORMULA:

Area = √ s(s-a)(s-b)(s-c)

where s = 1/2(a + b + c)

a, b, c are the three sides

But since the question insisted that we use 1/2* base * height. Let's use our know of right angle to dissolve that.

A right angle triangle has three sides. The longest is always the Hypotenuse.

Let's take it this way.

Hypotenuse = 30cm

Opposite= 18cm

Adjacent = 24cm

Area = 1/2 * base * height

Area = 1/2 * 18 * 24

Area = 1/2 * 432

Area = 216cm^2

We ignored the longest side, (the Hypotenuse)

6 0
2 years ago
What is 2/10 divided by 2/4
shtirl [24]

Given:

\dfrac{2}{10} divded by \dfrac{2}{4}.

To find:

The solution for the given division problem.

Solution:

We have, \dfrac{2}{10} divded by \dfrac{2}{4}. It can be written as

\dfrac{2}{10}\div \dfrac{2}{4}=\dfrac{2}{10}\times \dfrac{4}{2}

\dfrac{2}{10}\div \dfrac{2}{4}=\dfrac{2\times 4}{10\times 2}

\dfrac{2}{10}\div \dfrac{2}{4}=\dfrac{8}{20}

\dfrac{2}{10}\div \dfrac{2}{4}=\dfrac{2}{5}

Therefore, the solution for the given division problem is \dfrac{2}{5}.

3 0
3 years ago
John has $220 in his account and adds $25 to it each month Cheryl has $100 in her account and adds $35 each to her account. How
sammy [17]

Answer: In 12 months they will have the same amount, which will be $520.

Step-by-step explanation:

220 + 25m = 100 + 35m

m = month

Subtract 100 from each side

120 + 25m = 35m

Subtract 25m from each side

120 = 10m

Divide each side by 10

12 = m

4 0
3 years ago
Read 2 more answers
A camel had to walk a distance of 11,040 m. After 4 hours, he still had to walk 920 m. How far did the camel walk per hour?
sergey [27]

He walked 2,525 m per an hour.

11,040 - 920 = 10,100

10,100 / 4 = 2,525




Please mark brainliest.

7 0
3 years ago
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