You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
A cylinder has two bases and a height that (unless oblique) runs right along a side, while a cone has one base and whose height begins at the center of its base and goes straight up to the peak.
Answer:
The numbers are 17 and 5
Step-by-step explanation:
x + y = 22
x - y = 12
Add y to both sides of the equation
x = 12 + y
Substitute new value for x into first equation
12 + y + y = 22
Add the y's
12 + 2y = 22
Subtract 12 from both sides
2y = 10
y = 5
22 - 5 = 17
The numbers are 17 and 5
Hope this helps :)
