Answer:
Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.
Step-by-step explanation:
Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.
Given that he spent 5 hours in driving.
And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.
Given that his average rate in the morning was twice his average rate in the afternoon.
(150/x) = 2 * 50/(5-x)
150/x = 100/(5-x)
Cross multiplying terms, we get:-
150*(5-x) = 100*x
750 - 150x = 100x
750 = 100x + 150x
750 = 250x
x = 750/250 = 3.
It means he spent 3 hours in the morning and 2 hours in the afternoon.
So morning's average rate = 150/3 = 50 mph.
and afternoon's average rate = 50/(5-3) = 25 mph.
Answer:
Hop. Answer ur question the answer is 13
Step-by-step explanation:
yeah hope i helped
Answer:
12.6 cm
Step-by-step explanation:
Given:
m<AOB = θ = 120°
Diameter (d) = 12 cm
Required:
Length of arc AB
Solution:
Length of arc AB = θ/360 × πd
Plug in the values
Length of arc AB = 120/360 × π×12
≈ 12.6 cm (nearest tenth)
We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields
Move the 19 to the right hand side:
And square again:
Square one last time:
Let's check the solutions: all these squaring might have created external solutions:
So, 
is a feasible solution.
Answer:
the correct answer is 3 times the difference of 62 and 42
