What is the radius of a circle whose endpoints of a diameter are A(-4, 14) and B (2,8)
1 answer:
9514 1404 393
Answer:
3√2
Step-by-step explanation:
The length of the diameter is given by the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((2 -(-4))² +(8 -14)²) = √(36 +36) = 6√2
The radius is half the diameter, so the radius of your circle is 3√2.
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This is probably the answer I’m not 100% sure
log (4x-1) + 5 = 8
log (4x-1) = 8 - 5
log (4x-1) = 3
4x - 1 = 10³
4x - 1 = 1000
4x = 1001
x = 1001/4
ok done. Thank to me :>
