CAN SOMEONE HELP ME ON MY WORK PLEASE :( it’s on exponential functions

6 times the sum of a number and 5 is 16

Taya2010 [7]

6(n+5)=16
Solve for n to get your answer

7 0

3 years ago

Write an algebraic expression to represent each scenario.<br><br> Part A: “the sum of 6 and y”

Nostrana [21]

Answer:

6 + y

Step-by-step explanation:

Here, we want to write an algebraic expression to represent the situation

Mathematically, we want to add 6 and y

The algebraic expression will be;

6 + y

3 0

3 years ago

Assume that your present job pays a monthly gross salary of $1,560. You are offered a new position that pays $8.60 per hour with

motikmotik

Answer:

There are 4 weeks in a month and 40 working hours in a week

Since the $8.60 per hour, the gross monthly salary for your new position = 8.60*40*4 = $1,376

Your gross monthly salary at present job = $1,560

So the additional amount that you need to earn at your new position = 1,560-1,376 = $184

The hourly wage for addtional hours more than 40 hours at the new position = 1 1/2 * 8.60 = 1.5*8.60 = $12.90

So, number of hours that you need to work extra = 184/12.90 = 14.26 hours per month

So, number of hours that you need to work extra per week = 14.26/4 = 3.566 hours or 3.57 hours (Rounded to 2 decimals)

Step-by-step explanation:

4 0

3 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe

AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = $12m+60$

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

$12m+60 = 14n$ for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0

3 years ago