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3 years ago

A student in greece discovers a pottery bowl that contains 48 of its original amount of c-14

2 answers:

tatiyna3 years ago

4 0

O you know that N/N0 = .48 and k=.00001 (and e=2.718) Your equation becomes: .48 = 2.718*(.00001*t) NOTE: you probably mean.48=(2.718).00001t

Harman [31]3 years ago

4 0

i have all the same questions like this and one has yet to be answered

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Solve the proportion ASAP help do both questions

Strike441 [17]

Answer:

7. 4

8. 7

Step-by-step explanation:

7. $\frac{1}{2} = \frac{x}{8}$

Cross multiply

$1*8 = x*2$

$8 = 2x$

$\frac{8}{2} = \frac{2x}{2}$ (division property of equality)

$4 = x$

$x = 4$

8. $\frac{3}{x - 3} = \frac{6}{8}$

Cross multiply

$3*8 = 6(x - 3)$

$24 = 6x - 18$

$24 + 18 = 6x$ (addition property of equality)

$42 = 6x$

Divide both sides by 6

$7 = x$

$x = 7$

6 0

3 years ago

A pentagonal pyramid holds 30 cubic cm of sand. The area of the pentagon equals 9 square cm. Find the pyramid's height.

Aleksandr [31]

Answer =3.333333333 is the answer

30cm divided by 9 cm to get ur answer
In this case it is recurring

3 0

3 years ago

Read 2 more answers

The population of rabbits on an island is growing exponentially. In the year 1991, the population of rabbits was 9100, and by 19

lisabon 2012 [21]

Answer:

$39,223\ rabbits$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$y=a(1+r)^x$

where

y is the population of rabbits

x is the number of years since 1991

a is the initial value

r is the rate of change

we have

$a=9,100$

substitute

$y=9,100(1+r)^x$

For the year 1998

the number of years is equal to

x=1998-1991=7 years

we have the ordered pair (7,18,000)

substitute in the exponential equation and solve for r

$18,000=9,100(1+r)^7$

$(18,000/9,100)=(1+r)^7$

elevated both sides to 1/7

$(1+r)=1.1023$

$r=0.1023$

therefore

$y=9,100(1+0.1023)^x$

$y=9,100(1.1023)^x$

Predict the population of rabbits in the year 2006

Find the value of x

x=2006-1991=15 years

substitute the value of x in the equation

$y=9,100(1.1023)^{15}$

$y=39,223\ rabbits$

6 0

3 years ago

One leg of a right triangle is 4 cm the hypotenuse is 10 cm how long it the other leg

ASHA 777 [7]

I hope this will work.

3 0

3 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

2 years ago