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irina1246 [14]
4 years ago
7

What is the minimum y-value after which the exponential function will always be greater than the linear function? y = 1 y = 2 y

= 3 y = 4

Mathematics
2 answers:
Alenkinab [10]4 years ago
8 0

From the graph we can see that in the interval [0,1] the value of y is less than 1.

In the interval [1,2] the value of y value is 2 to 4.

In the interval [2,infinity) the graph is going up, and the value of y is greater than or equal to 4.

Therefore, the graph going up after y=4 above the line.

Therefore, the minimum y-value is 4 after which the exponential function will always be greater than the linear function.

Whitepunk [10]4 years ago
5 0

Answer:

y=4

Step-by-step explanation:

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The gradient of a straight line that passes
AURORKA [14]

Answer:

k=4

Step-by-step explanation:

We can use the slope formula

m = (y2-y1)/(x2-x1)

-2 = (k-2)/(-4 - -3)

-2 = (k-2)/(-4+3)

-2 = (k-2)/ ( -1)

Multiply by -1

-2 * -1 =  (k-2)/ ( -1) * -1

2 = k-2

Add 2 to each side

2+2 = k-2+2

4 =k

6 0
3 years ago
The value of n for the equation 5n = 5 11 × 5 3
ExtremeBDS [4]
If you add the two terms on the right, you will get 5^14. 14 is your answer.
3 0
4 years ago
While on your trip you get sick and eventually end up in the hospital. The doctor orders 120 mg of medicine to be given in the m
kenny6666 [7]

Answer:

4 tablets

Step-by-step explanation:

If the morning dose is 120mg and each tablet is 30mg then all you do is divide 120 by 30 to get the answer 4

4 0
3 years ago
Read 2 more answers
If ph term of A.P. is q and qth term is p, then (p+q) term is??​
kherson [118]

If the pth term of an arithmetic progression is q and qth term is p then the (p+q) th term is 0.

Given that the p th term of an A.P is q aand q th term is p.

We are required to find the (p+q) th term of that A.P.

Arithmetic progression is a sequence in which all the terms have common difference between them.

N th term of an A.P.=a+(n-1)d

p th term=a+(p-1)d

q=a+(p-1)d-------1

q th term=a+(q-1)d

p=a+(q-1)d---------2

Subtract equation 2 by 1.

q-p==a+(p-1)d-a-(q-1)d

q-p=pd-qd-d+d

q-p=d(p-q)

d=(p-q)/(q-p)

d=-(p-q)/(p-q)

d=-1

Put the value of d in 1.

q=a+(p-1)(-1)

q=a-p+1

a=q+p-1

(p+q) th term=a+(n-1)d

=q+p-1+(p+q-1)(-1)

=q+p-1-p-q+1

=0

Hence if the pth term of an A.P is q and qth term is p then the (p+q) th term is 0.

Learn more about arithmetic progression at brainly.com/question/6561461

#SPJ1

8 0
2 years ago
Question 3 (2 points)
djverab [1.8K]

Answer:

Hypothesis

a. If two integers are even

Conclusion

b. then their sum is even

Step-by-step explanation:

We divide the statement into two parts . The first part is true only when the second is also true. The only way we can reject the hypothesis is that the conclusion is false.

In the statement "If two integers are even, then their sum is even" the part "If two integers are even" would be considered true or false on the basis of "then their sum is even" validity. So if the "then their sum is even" (conclusion )  Part is proved then the "If two integers are even" ( hypothesis) is also true.

Hence the hypothesis is

a. If two integers are even

and

Conclusion is

b. then their sum is even

8 0
3 years ago
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