Find the area of the parallelogram with vertices k(1, 2, 2), l(1, 5, 3), m(3, 11, 3), and n(3, 8, 2).
Reil [10]
On examining the sides of the parallelogram, we see that the side KL lies in the plane x=1, and the side MN lies in the plane x=3.
Hence the height of the parallelogram is h=(3-1)=2.
The length of side mKL=sqrt((5-2)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
The length of side mMN=sqrt((11-8)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
Therefore the area of the parallelogram is mKL*h = sqrt(10)*2 = 2sqrt(10)
Answer: Area of parallelogram =
3 * 3 = 9 - 1 = 8
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Answer:
140
Step-by-step explanation:
We have been given two fractions and . We are asked to find the least common denominator of both fractions.
To find the least common denominator of both fractions, we will find least common multiple of 20 and 28.
Prime factorization of 20:
Prime factorization of 28:
Least common multiple of 20 and 28 would be: .
Therefore, the least common denominator of both fractions would be 140.
Given that the line passes through the two points (-3,4) and (2,8)
We need to determine the equation of the line.
<u>Slope:</u>
The slope of the line can be determined using the formula,
Substituting the points (-3,4) and (2,8) in the above formula, we get;
Thus, the slope of the line is
<u>Equation of the line:</u>
The equation of the line can be determined using the formula,
Substituting the point (-3,4) and in the above formula, we have;
Thus, the equation of the line is
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