All categories

3 years ago

What is 2 3/8 divided by 1 1/4... here the answers

Mathematics

2 answers:

alex41 [277]3 years ago

3 0

Answer:

B Step-by-step explanation:

Evgesh-ka [11]3 years ago

3 0

Answer:

Step-by-step explanation:

just ask Google and it will show as 1.9 which is 1 and 9/10

You might be interested in

If A={2,3,5,7} and B={2,4,6,8} then what is AnB?

gregori [183]

Answer:

A∩B = {2}

Step-by-step explanation:

It asks for the common set of A and B.

<u>There only one element common to both the given sets:</u>

A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}

6 0

3 years ago

Read 2 more answers

What is the solution set of the quadratic inequality 4(x+2)^2<_0?

sattari [20]

The solution is in the picture

8 0

3 years ago

Read 2 more answers

The final cost of a sale item is determined by multiplying the price on the tag by 75%. Which best describes the function that r

REY [17]

Answer:

It is linear because the ratio of the change in the final cost compared to the rate of change in the price tag is constant.

5 0

3 years ago

Read 2 more answers

Meagan is taking piano and gymnastics lessons. She has a piano lesson every 13 days and a gymnastics lesson every 6 days. When w

liraira [26]

the answer is 2

there are 13 days, 6x2=12. so the answer is 2.

6 0

3 years ago

Identify the lines that are perpendicular: A. = −5 and = 2 are perpendicularB. + 5 = 2 and − 5 + = 3 are perpendicularC. = 13 +

scZoUnD [109]

In order to check if the lines are perpendicular, we need to check if their slopes have the following relation (to find the slope we can use the slope-intercept form y = mx + b):

$m_1=-\frac{1}{m_2}$

In this option, y = -5 is an horizontal line and x = 2 is a vertical line, therefore they are perpendicular.

First let's find the slope of each line:

$\begin{gathered} x+\frac{y}{5}=2 \\ 5x+y=10 \\ y=-5x+10\to m=-5 \\ \\ -\frac{x}{5}+y=3 \\ y=\frac{x}{5}+3\to m=\frac{1}{5} \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y=\frac{1}{3}x+1\to m=\frac{1}{3} \\ \\ y-1=-3(x-5) \\ y-1=-3x+15 \\ y=-3x+16\to m=-3 \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y-5=x+1 \\ y=x+6\to m=1 \\ \\ x+y=3 \\ y=-x+3\to m=-1 \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y+2=\frac{1}{3}(x-6) \\ y+2=\frac{1}{3}x-2 \\ y=\frac{1}{3}x-4\to m=\frac{1}{3} \\ \\ y=3x+4\to m=3 \end{gathered}$

These slopes don't obey the relation stated above, so the lines aren't perpendicular.

The correct options are A, B, C and D.

5 0

1 year ago