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3 years ago

0.000387 in scientific notation

Mathematics

1 answer:

jasenka [17]3 years ago

8 0

Answer:

0.000387 = 3.87 × 10^-4

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(x+5)(3x+2) answer please

hichkok12 [17]

Answer:

$3x^{2} +17x+10$

Step-by-step explanation:

$(x+5)(3x+2)=\\3x^{2} +2x+15x+10=\\3x^{2}+17x+10$

8 0

3 years ago

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What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot

Phantasy [73]

Answer:

The zeros are

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

Step-by-step explanation:

we have

$f(x)=2x^{2}+8x-3$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

Equate the function to zero

$2x^{2} +8x-3=0$

$a=2\\b=8\\c=-3$

substitute in the formula

$x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}$

$x=\frac{-8\pm\sqrt{88}} {4}$

$x=\frac{-8\pm2\sqrt{22}} {4}$

$x=-2\pm\frac{\sqrt{22}}{2}$

therefore

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

4 0

4 years ago

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An ellipse has a center at the origin, a vertex along the major axis at (0, 17), and a focus at (0, −8).

MAVERICK [17]

Answer:

The last one.

Step-by-step explanation:

The standard form equation of an ellipse with foci on the y-axis is ...

y²/a² +x²/b² = 1

where "a" and "b" are the lengths of the semi-major and semi-minor axes, respectively. If "c" is the distance from the center to the focus, then this relation also holds:

b² +c² = a²

For this ellipse ...

b² + 8² = 17²

289 -64 = b² = 225 . . . . . subtract 8²

b = 15 . . . . . . . . . . . . . . . . . take the square root

The equation of the ellipse is then ...

y²/17² +x²/15² = 1

3 0

3 years ago

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Need help doing the steps I know the answer but i need to know the steps it took to get that answer

natka813 [3]

You would just break each one into 2 separate equations and solve for x/r. Then write the answer in between the two inequality signs- so the answers for 9 and 11 would look like this, just fill in the blanks with the answer you got: 3≤____<5, 2>___>-2.

0≤x-2<3
1≤x-2 and x-2<3

-1>2r-5>-9
-1>2r-5 and 2r-5>-9

this one just solve each one for z.
2z-1≤5 or 3z-5>10
z≤3 or x>5

3 0

3 years ago

15 POINTS! PLEASE HELP ME!

solmaris [256]

1. It's a rational number as it's written in fraction form.
2. It's a repeating because if you divide 62/495 you get 12.5252...(52 repeating)

5 0

3 years ago

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