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sergij07 [2.7K]
3 years ago
15

James has 6 stamps in his stamp collection, Roy has 12 stamps in his stamp collection. James adds 2 stamps to his collection. Af

ter James adds these stamps, what is the ratio of the number of stamps in James collection to the number of stamps in Roy’s collection
Mathematics
2 answers:
Romashka [77]3 years ago
6 0

Answer: <em>2:3, i think :)</em>

Reptile [31]3 years ago
6 0

Answer:

8:12, 8/12

Step-by-step explanation:

6+2= 8

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Your answer would be 24/25

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Find 12 +13 - (-9)+(-19.4) +3.3
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17.9

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You could use PEMDAS but you don't really need to because this is just adding an subtracting.

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The heights of adult males in the United States are approximately normally distributed. The mean height is 70 inches (5 feet 10
steposvetlana [31]

Using the normal distribution, it is found that the probability is 0.16.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, the mean and the standard deviation are given by, respectively, \mu = 70, \sigma = 3.

The proportion of students between 45 and 67 inches is the p-value of Z when <u>X = 67 subtracted by the p-value of Z when X = 45</u>, hence:

X = 67:

Z = \frac{X - \mu}{\sigma}

Z = \frac{67 - 70}{3}

Z = -1

Z = -1 has a p-value of 0.16.

X = 45:

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 70}{3}

Z = -8.3

Z = -8.3 has a p-value of 0.

0.16 - 0 = 0.16

The probability is 0.16.

More can be learned about the normal distribution at brainly.com/question/24663213

3 0
2 years ago
What is the solution to StartFraction 5 over 6 EndFraction x minus one-third greater-than 1 and one-third?
Vikentia [17]

Answer:

The correct answer is x > 2.

Step-by-step explanation:

\dfrac{5}{6} x - \dfrac{1}{3} > 1\dfrac{1}{3}

An inequality compares two quantities unlike an equality. An inequality is written with either a greater than ( > ) or lower than ( < ) or greater than equal to ( \geq ) or less than equal to ( \leq ) signs. We solve the above given inequality to find the solutions of the unknown x.

\dfrac{5}{6} x - \dfrac{1}{3} > 1\dfrac{1}{3} \\\dfrac{5}{6} x - \dfrac{1}{3} > \dfrac{4}{3} \\\dfrac{5}{6} x > \dfrac{1}{3} + \dfrac{4}{3} \\\dfrac{5}{6} x > \dfrac{5}{3}\\x > 2

Firstly we change the right hand side quantity to fraction.

We then transfer the - \frac{1}{3} to the right hand side and add them. The inequality sign does not change as we are simply adding or subtracting terms from both the ends.

Finally we divide both sides with \frac{6}{5} to get the required solution. The inequality sign does not change as we are multiplying both the ends with a positive quantity.

This gives us the answer as x > 2.

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3 years ago
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