All categories

3 years ago

Factor 20x2 + 25x – 12x – 15 by grouping

Mathematics

1 answer:

Mazyrski [523]3 years ago

4 0

Answer:

(4x+5)(5x-3)

Step-by-step explanation:

There you go! glad to help :)

You might be interested in

Find the 20th term in the sequence, where the first term is -2 and the common ratio is-2.

geniusboy [140]

Answer:

Step-by-step explanation:

(1)

a1=-2

r=-2

$a_{20}=(-2)(-2)^{20-1}=-2(-2)^{19}=2^{20}=1048576\\(2)\\a_{1}=1000\\r=\frac{200}{1000} =\frac{1}{5} \\a_{8}=1000(\frac{1}{5} )^{8-1}=1000(.2)^7=0.0128\\(3)\\a_{1}=2\\a_{3}=50\\a_{2}=\sqrt{2*50} =10\\r=\frac{10}{2} =5$

6 0

3 years ago

Loli-Land Candy Store sells a 12 ounce bag of 60 mints. What is the number of mints per ounce?

Vsevolod [243]

5 because you have to divide 60 by 12.

6 0

3 years ago

Find the number the comes next 1.2.6,21.88,?

Nataly_w [17]

Answer

455

Step-by-step explanation:

(1×1) + 1 = 2

(2×2) + 2 = 6

(6×3) + 3 = 21

(21×4)+4 = 88

(88×5)+5 = 445

5 0

2 years ago

Read 2 more answers

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

HELP???

zzz [600]

D(t)=25(0.82)^t

d(4)=11.3mg

6 0

3 years ago